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ryzh [129]
3 years ago
9

Please help i don't remember

Chemistry
1 answer:
SIZIF [17.4K]3 years ago
6 0

my answer here would be A. Hope this helps

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How many moles of oxygen will occupy a volume of 2.50 liters?
loris [4]
Data:
n (number of mols) = ? 
V (volume) = 2.50 Liters 
If: 
1 L → 1000 g
2.50 L → y

y = 1000*2.50 = 2500 g

Therefore:
m (mass) = 2500 g

Now:
Molar Mass (MM) of oxygen = 16 g/mol

Formula:
n =  \frac{m}{MM}

Solving:
n = \frac{m}{MM}
n = \frac{2500\:\diagup\!\!\!\!\!g}{16\:\diagup\!\!\!\!\!g/mol}
\boxed{\boxed{n = 156.25\:mols}}\end{array}}\qquad\quad\checkmark




7 0
3 years ago
Balance <br> Na2O+H2O → NaOH
AleksAgata [21]
Answer:
Na2O+H2O=2NaOH
Step by step exp.
Given:
Equation Na2O+H2O=NaOH
To find: Balance the equation
Solution:
Taking LHS of the equation
LHS=Na2O+H2O
There is 2 sodium, 2 oxygen,& 2 hydrogen
To balance the equation we have equal number of atom so we multply 2 to the RHS=2NaOH
There fore the equation form is
Na2O+H2O=2NaOH
8 0
3 years ago
The analysis of a compound gives the following percent composition by mass:
boyakko [2]

Answer:

C15 H31 O4 S

Explanation:

molecular formula is also the same because the value of "n" is 1

5 0
3 years ago
A tetraphenyl phosphonium chloride (TPPCl) powder (FW=342.39) is 94.0 percent pure. How many grams are needed to prepare 0.45 L
slega [8]

Answer:

5.41 g

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Or,

Moles =Molarity \times {Volume\ of\ the\ solution}

Given :

For tetraphenyl phosphonium chloride :

Molarity = 33.0 mM = 0.033 M (As, 1 mM = 0.001 M)

Volume = 0.45 L

Thus, moles of tetraphenyl phosphonium chloride :

Moles=0.033 \times {0.45}\ moles

Moles of TPPCl = 0.01485 moles

Molar mass of TPPCl = 342.39 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.01485\ g= \frac{Mass}{342.39\ g/mol}

Mass of TPPCl = 5.0845 g

Also,

TPPCl is 94.0 % pure.

It means that 94.0 g is present in 100 g of powder

5.0845 g is present in 5.41 g of the powder.

<u>Answer -  5.41 g</u>

5 0
3 years ago
Which of these statements is false? (A) Acetylene (ethyne) can be converted to the acetylide anion by treating with a strong bas
Free_Kalibri [48]

Answer:

(C) Acetylene (ethyne) can be converted to the acetylide anion by treating with a strong base such as CH₃​​Li.

Explanation:

Acetylene (C₂H₂) can be converted to the acetylide anion (C₂⁻²) when treated with a base because it will donate protons (2H⁺). So it will be a neutralization reaction. NaNH₂ and NaOH are strong bases because they are good electrons donators ( NaNH₂ has pair of electrons on N, and NaOH has the group OH⁻), but CH₃Li has no pair of electrons to donate, so it's not a strong base.

4 0
4 years ago
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