Answer: B. a chemical change
Explanation:
Answer:
0.15M
Explanation:
The equation for molarity is M= n/L. Where "M" is Molarity, "n" is the number of moles of solute, and "L" is the total liters in solution.
You need to calculate the number of moles from the given grams. The molar mass of KOH is (39.098+ 16 +1.008)= 56.106g. To calculate the mols of KOH, 
× 
= 0.44558... mol, you see that the grams unit cancel out leaving you with mol as the unit.
The volume is given in L already so no need to do any conversion. M= 
= 0.1485M ≈ 0.15M
<span>He should use a scale and record the weight in N. The beaker is used for liquid measurement and the scale is used for measuring sold things. A dumbbell is not a liquid material that is why the need of the scale will give it the accurate measurement that Hunter wants to know.</span>
Answer:
The solution is basic.
Explanation:
We can determine the nature of the solution via determining which has the large no. of millimoles (acid or base):
- If no. of millimoles of acid > that of base; the solution is acidic.
- If no. of millimoles of acid = that of base; the solution is neutral.
- If no. of millimoles of acid < that of base; the solution is basic.
- We need to calculate the no. of millimoles of acid and base:
no. of millimoles of acid (HNO₃) = MV = (1.3 M)(75.0 mL) = 97.5 mmol.
no. of millimoles of base (NaOH) = MV = (6.5 M)(150.0 mL) = 975.0 mmol.
<em>∴ The no. of millimoles of base (NaOH) is larger by 10 times than the acid (HNO₃).</em>
<em>So, the solution is: basic.</em>
Answer:
Explanation:
Hello,
In this case, we work on a dilution process in which we can state that the moles remain the same after the dilution process. In such a way, we can write:
That in terms of molarities and volumes is:
Whereas 
is the initial molarity (3.00 M) of the stock solution, 
the molarity of the diluted solution (0.289 M), 
the aliquot of the stock (concentrated) solution and 
the volume of the diluted solution (100 mL), thus, we compute as required:
Best regards.
