The molarity of acetic acid in the vinegar is 0.94 M
<u><em> calculation</em></u>
Step 1: write the balanced equation between CH3COOH + NaOH
that is CH3COOH + NaOH → CH3COONa + H2O
step 2 : find the moles of NaOH
moles =molarity x volume in L
volume in liters = 26.90/1000=0.0269 l
moles = 0.175 mol /L x 0.0269 L =0.0047 moles of NaOH
Step 3: use the mole ratio to find moles of CH3COOH
that is the mole ratio of CH3COOH: NaOH is 1:1 therefore the moles of CH3COOH is =0.0047 moles
Step 4: find the molarity of CH3COOH
molarity = moles/volume in liters
volume in liter = 5.00/1000 =0.005 l
molarity is therefore=0.0047 moles/ 0.005 l = 0.94 M
