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3 years ago

11

How does solar radiation affect the thermosphere? explain

1 answer:

Mashutka [201]3 years ago

5 0

"The sun radiates radiation in the UV, visible and infra-red regions of the spectrum. <span>When this reaches earth, some is reflected off the atmosphere/ clouds back into space. However, some passes through. UV </span>radiation<span> ionises molecules in the </span>thermosphere<span>, and this is the cause of the aurora." Credits to Google

Happy studying!</span>

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Insulin is a protein that is used by the body to regulate both carbohydrate and fat metabolism. A bottle contains 375 mL of insu

Kitty [74]

Mass = Density × Volume
= 30.0 mg / mL × 375 mL
= 11250 mg
= 11.25 g

∴ the total mass of insulin in the bottle is 11.25 g (11250 mg)

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2 years ago

What is the ph of a 0.014 M HCL solution?

Allushta [10]

Answer:

pH $= 1.853$

Explanation:

For every mole of hydrochloric acid, one mole of hydronium ion is required. Thus, in order to neutralize 0.014 moles of HCL, 0.014 moles of hydronium is required.

$[H_3O^+] = [HCl] = 0.014$

pH $= -log [H^+] = -log [H_3O^+]$

Substituting the available values in above equation, we can say that the pH of the solution is equal to

$- log (0.014)$

pH $= 1.853$

pH of a $0.014$ M HCL solution $= 1.853$

8 0

2 years ago

What is the mass of an atom that has 4 protons, 5 neutrons, and 4 electrons?

Mazyrski [523]

The answer would be 9

3 0

3 years ago

Read 2 more answers

Which picture or pictures show an element?

Westkost [7]

Its both A and C because both A and C have only one type each so it can only be those two :)

5 0

2 years ago

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c. The reaction Br2 (l) --> Br2 (g) has ΔH = 30.91 kJ/mol and ΔS = 93.3 J/mol·K. Use this information to show (within close a

egoroff_w [7]

Answer:

The answer to your question is given below.

Explanation:

From the question given above, the following data were obtained:

Br₂ (l) —> Br₂(g)

Enthalpy change (ΔH) = 30.91 KJ/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

Next, we shall convert 30.91 KJ/mol to J/mol. This can be obtained as follow:

1 KJ/mol = 1000 J/mol

Therefore,

30.91 KJ/mol = 30.91 × 1000

30.91 KJ/mol = 30910 J/mol

Thus, 30.91 KJ/mol is equivalent to 30910 J/mol.

Finally, we shall determine the boiling temperature of bromine. This can be obtained as follow:

Enthalpy change (ΔH) = 30910 J/mol

Entropy change (ΔS) = 93.3 J/mol·K

Boiling temperature (T) =?

ΔS = ΔH / T

93.3 = 30910 / T

Cross multiply

93.3 × T = 30910

Divide both side by 93.3

T = 30910 / 93.3

T = 331.29 K

Thus, the boiling temperature of bromine is 331.29 K

6 0

2 years ago