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2 years ago

What are two numbers that have a product of 15 but also a sum of 8

Mathematics

1 answer:

Kruka [31]2 years ago

5 0

Answer:

3 and 5

Step-by-step explanation:

3+5=8, and also

3x5=15

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Find the equation of the linear function 'g' going through (20,5) and (-5,-8). Use 'u' for your input variable.

frosja888 [35]

Answer:

See below

Step-by-step explanation:

Use the slope-intercept form, which will be in this case:

g(u) = mu + b, where m is the slope, b is the y- intercept

Find the slope:

$m=(y_2-y_1)/(x_2-x_1)$
$m=(-8-5)/(-5-20)=(-13)/(-25)=13/25$

Find the value of the y-intercept:

$5=1/25*20+b$
$b=5-4/5=21/5$

The equation is:

$g(u)=\frac{13}{25} u+\frac{21}{5}$

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2 years ago

The work of a student to solve a set of equations is shown:

Serhud [2]

In step 2 .. because when you multiple by -4 in step 1 , the equation in step 2 will be ( -4y =-16 + 8z)

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2 years ago

If f(x)=√2x+3/6x-5, then f(-1/2)=

denis23 [38]

answere=-1

this is the answere and the explanation.

8 0

3 years ago

Find the critical numbers of the function. (Enter your answers as a comma-separated list. Use n to denote any arbitrary integer

lyudmila [28]

$f(\theta)=10\cos\theta+5\sin^2\theta$

then the derivative is

$f'(\theta)=-10\sin\theta+10\sin\theta\cos\theta$

Critical points occur where $f'(\theta)=0$ . This happens for

$-10\sin\theta+10\sin\theta\cos\theta=0$

$-10\sin\theta(1-\cos\theta)=0$

$\implies-10\sin\theta=0\text{ or }1-\cos\theta=0$

In the first case, we find

$-10\sin\theta=0\implies\sin\theta=0\implies\theta=n\pi$

In the second,

$1-\cos\theta=0\implies\cos\theta=1\implies\theta=2n\pi$

So all the critical points occur at multiples of $\pi$ , or $n\pi$ . (This includes all the even multiples of $\pi$ .)

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3 years ago

If I weighed 12 stones and lost 5lb , how much would I weigh?

mamaluj [8]

Answer: 163 pounds

Step-by-step explanation: 12 stones is 168 pounds

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3 years ago

Read 2 more answers