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liq [111]
4 years ago
13

Worksheet 1.3

Mathematics
1 answer:
Lena [83]4 years ago
4 0

Answer:

<h2>50h miles</h2>

Step-by-step explanation:

For us to write a math expression for the problem, we will use the formula for calculating speed.

Speed is the change of distance of a body with respect to time.

Mathematically, Speed =  Distance/Time

Distance = Speed * Time

If  Lumpy drove for h hours at 50 mph, then Lumpy speed =  50mph and time = h hours.

Substituting the given parameters into the formula to get the distance;

Distance = 50mph * h hours

Distance = 50h miles

<em>Hence the math expression that modeled how far Lumpy drive is 50h miles</em>

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If you're using the app, try seeing this answer through your browser:  brainly.com/question/2866883

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First, differentiate implicitly both sides with respect to x. Keep in mind that y is not just a variable, but it is also a function of x, so you have to use the chain rule there:

\mathsf{\dfrac{d}{dx}(x^2 y-3x)=\dfrac{d}{dx}(y^3-3)}\\\\\\&#10;\mathsf{\dfrac{d}{dx}(x^2 y)-3\,\dfrac{d}{dx}(x)=\dfrac{d}{dx}(y^3)-\dfrac{d}{dx}(3)}


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\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3=3y^2\cdot \dfrac{dy}{dx}}\\\\\\&#10;\mathsf{2xy+x^2\cdot \dfrac{dy}{dx}-3-3y^2\cdot \dfrac{dy}{dx}=0}\\\\\\&#10;\mathsf{x^2\cdot \dfrac{dy}{dx}-3y^2\cdot \dfrac{dy}{dx}=-\,2xy+3}\\\\\\&#10;\mathsf{(x^2-3y^2)\cdot \dfrac{dy}{dx}=-\,2xy+3}


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I hope this helps. =)


Tags:  <em>implicit function derivative implicit differentiation chain product rule differential integral calculus</em>

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