Answer:
last option is the answer; all values greater than 12
Step-by-step explanation:
2/3x - 5 > 3
2/3x > 8
x > 24/2
x > 12
Im taking stats right now i might be able to help.
Answer:
tt
Step-by-step explanation:
7vito6u
This statement is false<span>. Because the </span>base angles<span> of an </span>isosceles triangle<span> are</span>congruent<span>, if one </span>base angle<span> is a right </span>angle<span> then both </span>base angles<span> must be right</span>angles<span>. It is impossible to have a </span>triangle<span> with two right (90^\circ)</span>angles<span>.</span>
Answer:
Part one: The function rule for the area of the rectangle is A(x) = 3x² - 2x
Part two: The area of the rectangle is 8 feet² when its width is 2 feet
Step-by-step explanation:
Assume that the width of the rectangle is x
∵ The width of the rectangle = x feet
∵ The length of the rectangle is 2 ft less than three times its width
→ That means multiply the width by 3, then subtract 2 from the product
∴ The length of the rectangle = 3(x) - 2
∴ The length of the rectangle = (3x - 2) feet
∵ The area of the rectangle = length × width
∴ A(x) = (3x - 2) × x
→ Multiply each term in the bracket by x
∵ A(x) = x(3x) - x(2)
∴ A(x) = 3x² - 2x
∴ The function rule for the area of the rectangle is A(x) = 3x² - 2x
∵ The rectangle has a width of 2 ft
∵ The width = x
∴ x = 2
→ Substitute x by 2 in A(x)
∵ A(2) = 3(2)² - 2(2)
∴ A(2) = 3(4) - 4
∴ A(2) = 12 - 4
∴ A(2) = 8
∴ The area of the rectangle is 8 feet² when its width is 2 feet
