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2 years ago

Z = ma for a please help

Mathematics

1 answer:

il63 [147K]2 years ago

3 0

Answer:

Z = Ma = ba

You made a typo. One of those = signs should either

be a + and a -. Here are all possibilities:

1. Z+Ma = ba, solve for a

Ma-Ba = -Z

a(M-B) = -Z

a = -Z/(M-B)

2. Z = Ma+ba, solve for a

Ma+ba = Z

a(M+b) = Z

a = Z/(M+b)

3. Z-Ma = ba, solve for a

Z = Ma+ba

Ma+ba = Z

a(M+b) = Z

a = Z/(M+b)

4. Z = Ma-ba, solve for a

Ma-ba = Z

a(M-b) = Z

a = Z/(M-b)

Step-by-step explanation:

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Marta wrote six and eighty hundredths. Nicky wrote six and eight tenths. Who wrote the greater number? explain

nataly862011 [7]

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3 years ago

PLEASE HELP AND GIVE AN EXPLANATION A rectangular prism has a volume of 170 cm the length of the prism is 5 cm in the height of

IgorC [24]

Answer:

The width of the prism is 2 cm

Step-by-step explanation:

The given parameters are;

The volume of the prism = 170 cm³

The length of the prism = 5 cm

The height of the prism = 17 cm

The volume of the prism is given by the relationship v = Length, l × Height, h × Width, w

Therefore;

The volume of the prism = 5 cm × 17 cm × w = 170 cm³

Which gives;

w = 170 cm³/(5 cm × 17 cm) = 170 cm³/(85 cm) = 2 cm

∴ The width of the prism = 2 cm.

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2 years ago

I need help with the steps. The answer is (5,2)

Elden [556K]

So with this, I will be using the substitution method. With the first equation, substitute (y+3) into the x variable and solve for y:

$y+3+y=7\\2y+3=7\\2y=4\\y=2$

Next, now that we have the value of y, substitute it into either equation to solve for x:

$x+2=7\\x=5\\\\x=2+3\\x=5$

<u>And this is how you get your final answer (5,2).</u>

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3 years ago

A manufacturing company produces 3 different products A, B, and C. Three types of components, i.e., X, Y, and Z, are used in the

Murljashka [212]

Answer:

Step-by-step explanation:

Using the Excel Formula:

Decision Variable Constraint Constraint

A 65 65 100

B 80 80 80

C 90 90 90

14100 300 300

= (150 *B3)+(80*B4) +(65*B5)-(100-B3+80-B4+90-B5)*90

Now, we have:

Suppose A, B, C represent the number of units for production A, B, C which is being manufactured

A B C Unit price

Need of X 2 1 1 $20

Need of Y 2 3 2 $30

Need of Z 2 2 3 $25

Price of

manufac - $200 $240 $220

turing

Now, for manufacturing one unit of A, we require 2 units of X, 2 units of Y, 2 units of Z are required.

Thus, the cost or unit of manufacturing of A is:

$20 (2) + $30(2) + $25(2)

$(40 + 60 + 50)

= $150

Also, the market price of A = $200

So, profit = $200 - $150 = $50/ unit of A

Again;

For manufacturing one unit of B, we require 1 unit of X, 3 units of Y, and 2 units of Z are needed and they are purchased at $20, $30, and 425 each.

So, total cost of manufacturing a unit of B is:

= $20(1) + $30(3) + $25(2)

= $(20 + 90+50)

= $160

And the market price of B = $240

Thus, profit = $240- $160

profit = $80

For manufacturing one unit of C, we have to use 1 unit of X, 2 unit of Y, 3 units of Z are required:

SO, the total cost of manufacturing a unit of C is:

= $20 (1) + $30(2) + $25(3)

= $20 + $60 + $25

= $155

This, the profit = $220 - $155 = $65

However; In manufacturing A units of product A, B unit of product B & C units of product C.

Profit --> 50A + 80B + 65C

This should be provided there is no penalty for under supply of there is under supply penalty for A, B, C is $40

The current demand is:

100 - A

80 - B

90 - C respectively

So, the total penalty

${(100 - A) + (80 - B) +(90 - C) } + \$40$

This should be subtracted from profit.

So, we have to maximize the profit

$Z = 50A + 80B + 65C = {(100 -A) + (80 - B) + (90 - C)};$

Subject to constraints;

we have the total units of X purchased can only be less than or equal to 300 due to supplies capacity

Then;

$2A + B +C \le 300$ due to 2A, B, C units of X are used in manufacturing A, B, C units of products A, B, C respectively.

Next; demand for A, B, C will not exceed 100, 80, 90 units.

Hence;

$A \le 100$

$B \le 80$

$C \le 90$

and $A, B, C \ge 0$ because they are positive quantities

The objective is:

$\mathbf{Z = 50A + 80B + 65 C - (100 - A + 80 - B + 90 - C) * 40}$

A, B, C $\to$ Decision Varaibles;

Constraint are:

$A \le 100 \\ \\ B \le 100 \\ \\ C \le 90 \\ \\2A + B + C \le 300 \\ \\ A,B,C \ge 0$

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2 years ago

How do you solve 1/2x x 3/5y=5

Anit [1.1K]

1/2 is a fraction so it is 5

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2 years ago

Read 2 more answers