Answer:
x = -1 and x = 4
Step-by-step explanation:
Firstly solve the quadratic expression of
2x^2-6x-8 = 0....it gives you the two brackets of.....(2x-8)(x+1)=0
then...you equate the two brackets to 0.separately
2x-8 = 0....which gives you...x = 4...as the first solution..then..;
x+1 = 0....which gives you...x = -1...as the second solution
Answer:
D
Step-by-step explanation:
I'm not certain but I guess that's it
If you do the long division you'll see that it is x - 2.
Given the equation - x² + 5x = 3, which can be rewritten as:
- x² + 5x - 3 = 0
where a = -1, b = 5 and c = -3.
Quadratic formula:
![\frac{-b\text{ }\pm\text{ }\sqrt[]{b^2\text{ - 4ac}}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7Bb%5E2%5Ctext%7B%20-%204ac%7D%7D%7D%7B2a%7D)
Now, we just replace the values of a, b and c on the equation above.
![\frac{-5\text{ }\pm\text{ }\sqrt[]{5^2\text{ - 4(-1)(3)}}}{2(-1)}](https://tex.z-dn.net/?f=%5Cfrac%7B-5%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Csqrt%5B%5D%7B5%5E2%5Ctext%7B%20-%204%28-1%29%283%29%7D%7D%7D%7B2%28-1%29%7D)
=
![\frac{5}{2}\text{ }\pm\text{ }\frac{\sqrt[]{13}}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B5%7D%7B2%7D%5Ctext%7B%20%7D%5Cpm%5Ctext%7B%20%7D%5Cfrac%7B%5Csqrt%5B%5D%7B13%7D%7D%7B2%7D)
Answer:
multiply both sides by 30 in fraction form 30 / 30
& 570 for the blank square for numerator of 30
Step-by-step explanation:
