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4 years ago

The master gland of the endocrine system is the: (2 points)

Physics

2 answers:

galben [10]4 years ago

8 0

Answer: Pituitary Gland

Explanation: The pituitary gland produces hormones that control other glands and body functions, therefore, it is sometimes called the master endocrine gland.

Ahat [919]4 years ago

4 0

The answer is pituitary hopes this helps

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If the temperature of the solar surface is 5800 K and Wien's law for the peak wavelength of the spectrum of the Sun, assumed to

enot [183]

Answer:

The dominant wavelength of the sun is $499.65nm$

Explanation:

Wien's law is defined as:

$\lambda_{max} T = c$ (1)

Where $\lambda_{max}$ is the maximum wavelength, c is the Wien's constant and T is the temperature.

Therefore, $\lambda_{max}$ can be isolated from equation 1.

$\lambda_{max} = \frac{c}{T}$ (2)

$\lambda_{max} = \frac{2.898x10^{-3}m\cdot K}{T}$

Notice that it is necessary to express the Wien's constant in units of meters

$c = 2.898x10^{-3}m\cdot K . \frac{1x10^{9}nm}{m}$ ⇒ $2.898x10^{6} nm \cdot K$

Finally, equation 2 can be used:

$\lambda_{max} = \frac{2.898x10^{6} nm \cdot K}{5800 K}$

$\lambda_{max} = 499.65nm$

Hence, the dominant wavelength of the sun is $499.65nm$

6 0

4 years ago

You catch a volleyball (mass 0.270 kg) that is moving downward at 7.50 m/s. In stopping the ball, your hands and the volleyball

sesenic [268]

Explanation:

The work done equals the change in energy.

W = ΔKE

W = 0 − ½mv²

W = -½ (0.270 kg) (-7.50 m/s)²

W = -7.59 J

Work is force times displacement.

W = Fd

-7.59 J = F (-0.150 m)

F = 50.6 N

3 0

4 years ago

Algunas fabricas de balones de fútbol ubicadas en la costa inflan los balones que van a ser vendiéndose las ciudades como pasto,

otez555 [7]

Answer:

balloon is rigid the amount of gas is constant inside the interior pressure of the balloon is constant and in these cities it becomes equal to or slightly higher than atmospheric pressure

Explanation:

Este ejercicio es referente a la mecánica de fluidos, usemos la expresión para la presión

P = ρ g h

En es el caso del balón usemos la presión en la pared extrema, llamemos P la presión por el gas en el interior y P_ext la presión atmosférica del lugar

cuando se llena el valor en una ciudad de baja altura la presión atmosférica es mas alta

P_int1 < P_ext1

por lo cual la pared del balón no se mantiene rígida.

Cuando el balón es trasladado a una ciudad con mayor altura sobre el nivel del mar la presión exterior disminuye

P_ext2 = ρ g h₂ < P_ext1

en promedio la presión disminuye con la altura en 0,029 atm cada 250 m

por lo tanto como la cantidad de gas es constante en el interior la presión interior del globo es constante y en esta ciudades se hace igual o un poco mayor que la presión atmosférica, en consecuencia la pared del globo esta rígida

P_int2 >P_ext2

Traslate

This exercise is related to fluid mechanics, let's use the expression for pressure

P = ρ g h

In the case of the balloon, let's use the pressure on the extreme wall, let's call P the pressure for the gas inside and P_ext the atmospheric pressure of the place

when the value is filled in a low-lying city the atmospheric pressure is higher

P_int1 <P_ext1

therefore the wall of the ball does not remain rigid.

When the ball is transferred to a city with higher altitude above sea level, the external pressure decreases

P_ext2 = ρ g h <P_ext1

on average the pressure decreases with height by 0.029 atm every 250 m

therefore as balloon is rigid the amount of gas is constant inside the interior pressure of the balloon is constant and in these cities it becomes equal to or slightly higher than atmospheric pressure, therefore the wall of the

Pint 2> Pe

8 0

3 years ago

Two wires are made from the same material. One wire has a resistance of 0.10 ω. The other wire is twice as long as the first wir

Anna71 [15]

Answer:

Explanation:

Given that,

First wire has a resistance of

R1 = 0.1 Ω

We are told that

Second wire is twice as long as the first wire.

Then,

Let the first wire has length

L1 = x

Then, second wire will have

L2 = 2x

Also, the radius of the second wire is half the radius of the first wire

Let the first wire has radius

r1 = y

Then, it area is

A1 = πr1² = πy²

Then, the second wire has radius

r2 = ½y

It area is also

A2 = πr2² = π(½y)² = ½πy²

Since the wire is made of the same material, then, they will have the same resistivity ρ

Then, we want to find the resistance of the second wire

Using

R = ρL/A

Where

R = resistance

ρ = sensitivity

L = length

A = area

Then, make resistivity subject of formula since it is a constant

RA = ρL

Then, ρ = RA/L

Then,

R1 • A1 / L1 = R2 • A2 / L2

Substituting each value

0.1 × πy² / x = R2 × ¼πy² / 2x

Cross multiply

0.1 × πy² × 2x = R2 ×¼π y² × x

Then,

R2 = 0.1 × πy² × 2x / ¼πy² × x

R2 = 0.1 × 2 / ¼

R2 = 0.8Ω

The resistance of the second wire is 0.8Ω

6 0

4 years ago

When does PE equal KE?

dybincka [34]

PE equals KE when KE is 50%.

Like below:

E = PE + KE
E = 50 + 50
E = 100.

Remember, both KE and PE always have to add up to 100 so that is why PE is equal to KE when KE is 50% of energy.

Hope I helped. :)

4 0

3 years ago