Given values:
Mass of the steel ball, m = 100 g = 0.1 kg
Height of the steel ball, h1 = 1.8 m
Rebound height, h2 = 1.25 m
a. PE= mgh
0.1 x 9.8 x 1.8 =
1.764 Joules
b. KE = PE ->
1.764 Joules
c. KE= 1/2 mv square
so v = square root 2ke/m
square root 2 x 1.764/ 0.1
= 5.93 m/s
d. KE=PE=mgh square
0.1 x 9.8 x 1.21 =
1.186 joules
velocity of rebond is square root 2x 1.186/ 0.1 = 4.87 m/s
Answer:
1. the voltage will be 2.35×12.5 = 29.4V
2. the resistance would be 9.0/6.2= 1.45ohms
3. in series they will add up thus 4+8+12= 24ohms
4. in parallel it will be 2.18ohms
Answer:
Explanation:
The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:
(1)
- c is the speed of light (3*10⁸ m/s)
- μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
- B₀ is the magnetic field
Now, let's define the relationship between power (P) and average intensity (I).
- P is the power
- A is the area crossed
So we can calculate the power.
Finally, energy is the product of P times time, so:
I hope it helps you!
Answer:
C
Explanation:
Angular momentum is the product of moment of inertia and angular velocity.
L = I × ω
Since the planet follows a stable circular orbit, I and ω are constant and non-zero. Therefore, the angular momentum is constant and non-zero.
