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Tpy6a [65]
2 years ago
13

Find all complex solutions of 5x^2+5x+3=0.

Mathematics
1 answer:
oksian1 [2.3K]2 years ago
5 0

Answer:

see explanation

Step-by-step explanation:

5x² + 5x + 3 = 0 ← in standard form

with a = 5 , b = 5 , c = 3

Solve using the quadratic formula

x = \frac{-b+/-\sqrt{b^2-4ac} }{2a}

  = \frac{-5+/-\sqrt{5^2-(4(5)(3)} }{2(5)}

  = \frac{-5+/-\sqrt{25-60} }{10}

  = \frac{-5+/-\sqrt{-35} }{10}

  = \frac{-5+/-\sqrt{-1(35)} }{10}

 = \frac{-5+/-i\sqrt{35} }{10}

Then

x = \frac{-5}{10} ± \frac{1}{10} i\sqrt{35} , that is

x = - \frac{1}{2} - \sqrt{x} \frac{1}{10} i\sqrt{35} , - \frac{1}{2} + \frac{1}{10} i\sqrt{35}

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5 0
3 years ago
HELP++++++++++++++++++++++++
lys-0071 [83]

Answer:

ASA

ΔFGH ≅ ΔIHG ⇒ answer B

Step-by-step explanation:

* Lets revise the cases of congruence  

- SSS  ⇒ 3 sides in the 1st Δ ≅ 3 sides in the 2nd Δ

- SAS ⇒ 2 sides and including angle in the 1st Δ ≅ 2 sides and  

 including angle in the 2nd Δ

- ASA ⇒ 2 angles and the side whose joining them in the 1st Δ  

 ≅ 2 angles and the side whose joining them in the 2nd Δ

- AAS ⇒ 2 angles and one side in the first triangle ≅ 2 angles  

 and one side in the 2ndΔ  

- HL ⇒ hypotenuse leg of the first right angle triangle ≅ hypotenuse

 leg of the 2nd right angle Δ

* Lets prove the two triangles FGH and IHG are congruent by on of

 the cases above

∵ FG // HI and GH is transversal

∴ m∠FGH = m∠IHG ⇒ alternate angles

- In the two triangles FGH and IHG

∵ m∠FHG = m∠IGH ⇒ given

∵ m∠FGH = m∠IHG ⇒ proved

∵ GH = HG ⇒ common side

∴ ΔFGH ≅ ΔIHG ⇒ ASA

* ASA

 ΔFGH ≅ ΔIHG

3 0
3 years ago
What percentage of 440 is 325
GuDViN [60]

The answer would be 73.86

3 0
2 years ago
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Answer:

The slope = 3/4

Step-by-step explanation:

m=\frac{y_{2}-y_{1}  }{x_{2}-x_{1}  }

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5 0
2 years ago
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HELP AND I WILL GIVE BRAINLIEST
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Answer:

Step-by-step explanation:

6 0
3 years ago
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