2x+10 x + 3
------------ = --------------
10 4
4(2x+10) = 10(x+3)
8x + 40 = 10x + 30
2x = 10
x = 5
AE =2x+10 = 2(5) +10 = 20
answer
20 units
Answer:
1. Option C is correct
2. Option A is correct
3. Option C is correct
4. Option B is correct
5. Option D is correct
Step-by-step explanation:
1. x^2-3x-18/x+3
Factorize the numerator
x^2-6x+3x-18/x+3
x(x-6)+3(x-6)/x+3
(x+3)(x-6)/x+3
x-6
x-6 where x≠6
Option C is correct.
2. x-2/x^2+4x-12
Factorizing the denominator
x-2/x^2+6x-2x-12
x-2/x(x+6)-2(x+6)
x-2/(x-2)(x+6)
1/x+6
1/x+6 where x≠-6
Option A is correct.
3. 5x^3/7 x^3+x^4
5x^3/7x^3+x^4
5x^3/x^3(7+x)
5/7+x
Option C is correct
5/7+x where x≠-7
4. Simplify x/6x-x^2
x/6x-x^2
x/x(6-x)
1/6-x
Option B is correct
1/6-x where x≠6
5. 2/3a * 2/a^2
Multiplying both terms
4/3a^3
Option D is correct.
4/3a^3 where a≠0
Answer:
41.7feet
Step-by-step explanation:
From the question we are given the following
angle of depression = 50°
Distance of the pole from the base of the feet = 35feet (Adjacent)
Required
height of the school (opposite)
Using the SOH CAH TOA identity
Tan theta = opp/adj
Tan 50 = H/35
H = 35tan 50
H = 35(1.1918)
H = 41.7feet
Hence the height of the school is 41.7feet
Its easy to convert 86 kilometers per hour to meters per second :
Just divide the speed which is 86 by 3.6
86 divide 3.6 = 24 m/s or meter per second
V1=(T1/T2)*V2
In this problem, since you are given no actual numbers, the only thing you can do is multiply V2 over to get V1 alone. Since you can't cancel anything out, you are left with the answer above.
