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3 years ago

Decimal place value for nine and twenty six hundredths

Mathematics

1 answer:

tatuchka [14]3 years ago

4 0

The decimal point value for nine and twenty-six hundreths would be 9.26

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Consider the curve defined by the equation y=6x2+14x. Set up an integral that represents the length of curve from the point (−2,

torisob [31]

Answer:

32.66 units

Step-by-step explanation:

We are given that

$y=6x^2+14x$

Point A=(-2,-4) and point B=(1,20)

Differentiate w.r. t x

$\frac{dy}{dx}=12x+14$

We know that length of curve

$s=\int_{a}^{b}\sqrt{1+(\frac{dy}{dx})^2}dx$

We have a=-2 and b=1

Using the formula

Length of curve= $s=\int_{-2}^{1}\sqrt{1+(12x+14)^2}dx$

Using substitution method

Substitute t=12x+14

Differentiate w.r t. x

$dt=12dx$

$dx=\frac{1}{12}dt$

Length of curve= $s=\frac{1}{12}\int_{-2}^{1}\sqrt{1+t^2}dt$

We know that

$\sqrt{x^2+a^2}dx=\frac{x\sqrt {x^2+a^2}}{2}+\frac{1}{2}\ln(x+\sqrt {x^2+a^2})+C$

By using the formula

Length of curve= $s=\frac{1}{12}[\frac{t}{2}\sqrt{1+t^2}+\frac{1}{2}ln(t+\sqrt{1+t^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}[\frac{12x+14}{2}\sqrt{1+(12x+14)^2}+\frac{1}{2}ln(12x+14+\sqrt{1+(12x+14)^2})]^{1}_{-2}$

Length of curve= $s=\frac{1}{12}(\frac{(12+14)\sqrt{1+(26)^2}}{2}+\frac{1}{2}ln(26+\sqrt{1+(26)^2})-\frac{12(-2)+14}{2}\sqrt{1+(-10)^2}-\frac{1}{2}ln(-10+\sqrt{1+(-10)^2})$

Length of curve= $s=\frac{1}{12}(13\sqrt{677}+\frac{1}{2}ln(26+\sqrt{677})+5\sqrt{101}-\frac{1}{2}ln(-10+\sqrt{101})$

Length of curve= $s=32.66$

5 0

3 years ago

A mattress store received a shipment of ten mattresses. Before the shipment, it had 782 mattresses in stock. How many mattresses

Vikentia [17]

Answer:

uh 792?

Step-by-step explanation:

782

+ 10

----------

792

7 0

2 years ago

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Is it possible to trisect any angle using only a compass and a straight edge

xeze [42]

Hello from MrBillDoesMath!

Answer:

No. That problem cited is one of 3 great unsolved problems of antiquity. See https://en.wikipedia.org/wiki/Angle_trisection for details.

Regards,

MrB

P.S. I'll be on vacation from Friday, Dec 22 to Jan 2, 2019. Have a Great New Year!

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3 years ago

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14 through 19 whole problem solving and answers

Sergio039 [100]

SEE THE PICTURE!~,BELOW~

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3 years ago

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16,500 rounded to nearest ten thousand

kari74 [83]

Hi,

16,500 rounded to the nearest ten thousand is 20,000.

Have a great day!

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3 years ago

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