Decimal place value for nine and twenty six hundredths

Bradley made a house for his dog, Bowser, out of wood with a cube base and a triangular prism top. The dimensions of the dog hou

Luda [366]

The complete question is
Bradley made a house for his dog, Bowser, out of wood with a cube base and a triangular prism top. The dimensions of the dog house are a = 2 feet, b = 1 foot, and c = 1.4 feet.
If Bradley plans to paint the outside of the dog house blue, not including the bottom, how many square feet of paint will he use?

the picture in the attached figure

we know that

surface area of the figure=surface area of cube+surface area of triangular prism

surface area of cube=4*a²----> 4*2²-----> 16 ft²

surface area of triangular prism=2*[a*c]+2*[a*b/2]---> 2*[2*1.4]+[2*1]
surface area of triangular prism=5.6+2----> 7.6 ft²

surface area of the figure=16 ft²+7.6 ft²----> 23.6 ft²

the answer is
23.6 ft²

7 0

3 years ago

Read 2 more answers

Hi, who wanna talk? I'm bored!

skelet666 [1.2K]

Answer:

Hello!!!!!!!!!!!!

4 0

3 years ago

Read 2 more answers

The Question is: Write 1/3 and 3/4 as a pair of fractions with a common denominator

cupoosta [38]

1/3*4= 4/12
3/4*3= 9/12
Answer is 4/12 and 9/12.

5 0

3 years ago

Someone help please❤️ & Thankyou!!

S_A_V [24]

Answers:

300 = 12i+36s
i = 10
Yes it's reasonable
i = -11

Refer to the diagram below.

The explanation for each part is below as well.

========================================================

Part 1

i = number of individual nail polish bottles

s = number of sets of 4

12i = money earned from just selling the individual bottles only

36s = money earned from just selling the sets of 4 only

12i+36s = total money earned = 300

12i+36s = 300 is the equation to set up

This is the same as 300 = 12i+36s because A = B is the same as B = A.

========================================================

Part 2

Plug in s = 5 to represent she sold 5 sets. Let's solve for i

12i+36s = 300

12i+36(5) = 300

12i+180 = 300

12i = 300-180

12i = 120

i = 120/12

i = 10

If she wants to sell $300 worth of product overall, and she already sold 5 sets so far, then she needs to sell 10 individual bottles to reach this monthly goal.

========================================================

Part 3

Yes it's reasonable to reach this goal. This is because the value of i (from part 2) was some positive whole number.

========================================================

Part 4

We'll repeat part 2 but with s = 12

12i+36s = 300

12i+36(12) = 300

12i+432 = 300

12i = 300-432

12i = -132

i = -132/12

i = -11

As the instructions state, we get a negative value. This is not reasonable because we can't sell a negative number of items. A negative number of items in general doesn't make sense.

The instructions further state that $432 was already made and that she exceeded her goal. Meaning that she doesn't have to worry about selling the individual bottles if selling the sets has her reach something over $300.

6 0

3 years ago

Given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle

Anastasy [175]

Answer:

Part 1) False

Part 2) False

Step-by-step explanation:

we know that

The equation of the circle in standard form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

where

(h,k) is the center and r is the radius

In this problem the distance between the center and a point on the circle is equal to the radius

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Part 1) given the center of the circle (-3,4) and a point on the circle (-6,2), (10,4) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x+3)^{2} +(y-4)^{2}=r^{2}$

Find the distance (radius) between the center (-3,4) and (-6,2)

substitute in the formula of distance

$r=\sqrt{(2-4)^{2}+(-6+3)^{2}}$

$r=\sqrt{(-2)^{2}+(-3)^{2}}$

$r=\sqrt{13}\ units$

The equation of the circle is equal to

$(x+3)^{2} +(y-4)^{2}=(\sqrt{13}){2}$

$(x+3)^{2} +(y-4)^{2}=13$

Verify if the point (10,4) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=10,y=4

substitute

$(10+3)^{2} +(4-4)^{2}=13$

$(13)^{2} +(0)^{2}=13$

$169=13$ -----> is not true

therefore

The point is not on the circle

The statement is false

Part 2) given the center of the circle (1,3) and a point on the circle (2,6), (11,5) is on the circle.

true or false

substitute the center of the circle in the equation in standard form

$(x-1)^{2} +(y-3)^{2}=r^{2}$

Find the distance (radius) between the center (1,3) and (2,6)

substitute in the formula of distance

$r=\sqrt{(6-3)^{2}+(2-1)^{2}}$

$r=\sqrt{(3)^{2}+(1)^{2}}$

$r=\sqrt{10}\ units$

The equation of the circle is equal to

$(x-1)^{2} +(y-3)^{2}=(\sqrt{10}){2}$

$(x-1)^{2} +(y-3)^{2}=10$

Verify if the point (11,5) is on the circle

we know that

If a ordered pair is on the circle, then the ordered pair must satisfy the equation of the circle

For x=11,y=5

substitute

$(11-1)^{2} +(5-3)^{2}=10$

$(10)^{2} +(2)^{2}=10$

$104=10$ -----> is not true

therefore

The point is not on the circle

The statement is false

7 0

3 years ago