To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
The average rate of change of g(x) between x = 4 and x = 7 is . Which statement must be true?
Subtract both fractions. Convert both fractions into improper fractions. So do 3x10+9 and see what ur answer is and put it over ten. Then do 2x16+1 and put the answer u get over 6. Then find the common denominator which is 30. Then subract both fractions and u should get ur answer
m = 4b+3 mikes age
m +b <138 mike +brother less than 138
4b+3+b<138
5b +3< 138
b< 135
b <27
The oldest the brother can be is 26
I would the answer to x is 12
