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Dafna1 [17]
3 years ago
7

Find the reciprocal of the number. Multiply to check your answer.

Mathematics
2 answers:
lubasha [3.4K]3 years ago
8 0
I think it would be B


Mars2501 [29]3 years ago
5 0
To find the reciprocal of a fraction, you just need to "flip" it. To check your work, you multiply the fraction and the reciprocal to get 1.

the reciprocal if 2/3 is 3/2

\frac{2}{3} * \frac{3}{2} = \frac{6}{6} = 1


The answer is B
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Order decimals from least to greatest .. 1.09, 1.901,1.9,1.19
Nuetrik [128]
The easiest way to do this is to write the decimals with equal amount of places after the dot and you'll see it more clearly:

1.09 = 1.090
1.901 = 1.901
1.9 = 1.900
1.19 = 1.190

So from the least to the greatest:

1.090
1.190
1.900
1.901

In a form you gave at the beginning:

1.09 < 1.19 < 1.9 < 1.901
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3 years ago
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alexgriva [62]

Answer:

The absoloute value is 2

Step-by-step explanation:

absoloute value is the places away from 0. -2 is 2 spots away from 0.

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3 years ago
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Solve the following system
scZoUnD [109]

Answer:

{x = -4 , y = 2 ,  z = 1

Step-by-step explanation:

Solve the following system:

{-2 x + y + 2 z = 12 | (equation 1)

2 x - 4 y + z = -15 | (equation 2)

y + 4 z = 6 | (equation 3)

Add equation 1 to equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - 3 y + 3 z = -3 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Divide equation 2 by 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+y + 4 z = 6 | (equation 3)

Add equation 2 to equation 3:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+5 z = 5 | (equation 3)

Divide equation 3 by 5:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y + z = -1 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 3 from equation 2:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x - y+0 z = -2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Multiply equation 2 by -1:

{-(2 x) + y + 2 z = 12 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract equation 2 from equation 1:

{-(2 x) + 0 y+2 z = 10 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Subtract 2 × (equation 3) from equation 1:

{-(2 x)+0 y+0 z = 8 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Divide equation 1 by -2:

{x+0 y+0 z = -4 | (equation 1)

0 x+y+0 z = 2 | (equation 2)

0 x+0 y+z = 1 | (equation 3)

Collect results:

Answer:  {x = -4 , y = 2 ,  z = 1

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Answer:

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Step-by-step explanation:

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Eva8 [605]

Answer: a

Step-by-step explanation:

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