Answer:
72 +1 , If u = A 8 1 - 2 ( ( + + +1 )– flog ( 3 + 3 / 3 ) ? v1m * + n + 13 ) 4 1 ; then 2 If c ... of any number of such MATHEMATICS . triangles ; and ( 3 ) find the mean value of ... 72 = 62 + 69 , 73 = 82 + 39 , 75 = 72 + 52 . the in - centre and centroid . ... 4n + 1 , or 4n + 2 ,
Step-by-step explanation:
The mean is
A. 8.4
B.5.2
C.9.4
2
2x
2
+5x−12
1 Split the second term in
2
x
2
+
5
x
−
1
2
2x
2
+5x−12 into two terms.
2
x
2
+
8
x
−
3
x
−
1
2
2x
2
+8x−3x−12
2 Factor out common terms in the first two terms, then in the last two terms.
2
x
(
x
+
4
)
−
3
(
x
+
4
)
2x(x+4)−3(x+4)
3 Factor out the common term
x
+
4
x+4.
(
x
+
4
)
(
2
x
−
3
)
(x+4)(2x−3)
Answer:
Does this help?
Step-by-step explanation:
2 = 4x + 12 and angle 4 = 7x - 6
Use the slope-intercept form to find the slope and y-intercept.
Slope: 0
y-intercept: 4
Use the slope-intercept form to find the slope and y-intercept.
Slope: 0
y-intercept: 2
Use the slope-intercept form to find the slope and y-intercept.
Slope: 0
y-intercept: 4
Graph 2= 4x + 12
Slope: Undefined
y-intercept: No y-intercept
Plot each graph on the same coordinate system.
4=
2=
4=
2= 4x + 12
4= 7x − 6
The length of the longer ship in terms of number of football fields is;
<u><em>4 football fields</em></u>
Let the length of ship 1 be x
Let the length of ship 2 be y
Total length of both ships is 2321 ft
Thus;
x + y = 2321 ----(eq 1)
The difference in their lengths is 17 ft
Thus;
x - y = 17 ----(eq 2)
Add eq 1 to eq 2 to get;
2x = 2338
Thus; x = 2338/2
x = 1169 ft
Put 1169 for x in eq 1 to get;
1169 + y = 2321
y = 2321 - 1169
y = 1152 ft
Longer ship = 1169 ft long
From conversion tables;
1 ft = 1/3 yards
Thus; 1169 ft = 1169 * 1/3 = 389.67 yards
A football field has a length of 100 yards
Then number of football fields for the length of the longer ship = 389.67/100 = 3.8967 ≈ 4 football fields.
Read more at; brainly.com/question/21804970
