Answer:
J
-66
Step-by-step explanation:
a1 = 2
n = 18
d = - 4
a18 = a1 + (n - 1) * d
a18 = 2 + (18 - 1)*(-4)
a18 = 2 + 17*-4
a18 = 2 - 68
a18 = -66
A. How many kilowatt hours of electricity did the Smiths use during February?
Kilowatt hours of electricity the Smiths used during February:
Meter read on March 1 - meter read on February 1 =
20,288 kilowatt hours - 19,423 kilowatt hours =
865 kilowatt hours
Answer: The Smiths used 865 kilowatt hours of electricity during February
b. How many kilowatt hours did they use during March?
Kilowatt hours of electricity the Smiths used during March:
Meter read on April 1 - meter read on March 1 =
21,163 kilowatt hours - 20,288 kilowatt hours =
875 kilowatt hours
Answer: The Smiths used 875 kilowatt hours of electricity during March
<span>(2^3)^5
=2^(3*5)
= 2^15
hope it helps</span>
Volume of the carton = 1000 cubic inches. Dimensions of a carton are 10"×10"×10"
Initial cost = $30,000
Depreciation rate = 2.5%
Depreciation expense per year = 30,000*2.5/100 = $750
In six years,
Depreciation = 6*750 = $4,500
Value of the tractor = Initial cost - Depreciation = $30,000 - $4,500 = $25,500
