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nexus9112 [7]
3 years ago
6

What is the surface area of this solid, to one decimal place

Mathematics
2 answers:
aleksandrvk [35]3 years ago
6 0

Step-by-step explanation:

\sf{7 \times 2 \times 5 = 70}

Hope this helps you.

Let me know if you have any other questions :-):-)

elixir [45]3 years ago
6 0
It is 7x2x5=70 hope this gets you a good grade
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HEEELLLPPP AREA QUESTION!!! BRAINLIEST AND 25 POINTZZ!!!
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b)area of rectangle-(area of two triangles)
(24×11)-(0.5×10×4+0.5×4×5)
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4 years ago
Eleanor has and 8 times 10 garden, she has 30 square yards of tomatoes. How does the percentage of tomatoes in Elanor's garden c
DanielleElmas [232]

Answer:

we are finding the least common multiple

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Step-by-step explanation:

6 0
3 years ago
What is the value of x?
Oliga [24]

Answer:

<u>x = 14</u>

Step-by-step explanation:

4x + (2x + 6) = 90

6x + 6 = 90

subtract both sides by 6:

6x + 6 <em>- 6 </em>=<em> </em>90 <em>- 6</em>

6x = 84

divide both sides by 6

6x/6 = 84/6

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double check:

4*14 + (2*14 + 6) = 90

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Have a nice day!

6 0
3 years ago
Read 2 more answers
Im not sure if this is correct. I need help!​
Rus_ich [418]

Answer:

Option 3

Step-by-step explanation:

If (x, y) is on h(x), then (y, x) is on the inverse.

Thus, if (4, 2) is on the inverse, then (2, 4) must be on the original. (Which it is not, so this option is incorrect)

If (0, 1/2) is on the inverse, then (1/2, 0) must be on the original. (It is not, so this option is also incorrect)

If (0, 1) is on the inverse, then (1, 0) must be on the original. (It is not, so this option is also incorrect)

If (-5, 1) is on the inverse, then (1, -5) must be on the original. (It is not, so this option is incorrect)

The correct answer would be the third option.

5 0
3 years ago
Order these from least to greatest [25 points]
VMariaS [17]

Answer:

\frac{\sqrt{6} }{4}, 1.538..., \frac{19}{7}, \sqrt{29}

Step-by-step explanation:

Solve them each on the calculator and then put in order

\frac{\sqrt{6} }{4} = 0.6123...

19/7 = 2.714

\sqrt{29} = 5.385...

8 0
3 years ago
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