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HACTEHA [7]
2 years ago
10

A line has a slope of -2/3 and passes through the point (-3,8). What is the equation of the line?

Mathematics
2 answers:
USPshnik [31]2 years ago
8 0

Answer:y=-2/3x+6

Step-by-step explanation:

took unit test on edge2020

LiRa [457]2 years ago
7 0

Answer:

Step-by-step explanation:

We'll use the standard equation y=mx+b to solve this problem. m is the slope of the line and b is the y intercept.

We know the slope, but we have to solve for the y intercept. To do this (I mean solve for 'b'), we need to know the slope, x value, and y value. We know the slope (-2/3), x= -3, and y=8. Let's plug this into y=mx+b and solve for b.

y=mx+b\\8=-\frac{2}{3}*-3 +b\\8=2+b\\b=8-2\\b=6

Let's plug all of this back into the first equation y=mx+b.

y=mx+b\\y=-\frac{2}{3}x+6

That's the answer to this problem.

I hope this helps.

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Y=3x + 4<br>What is the slope?​
slega [8]

Answer:

3

Step-by-step explanation:

In a slope intercept linear equation, the slope is always the number in front of the x value in an equation like y = mx + b.

So the slope is the 3 in front of the x value.

6 0
2 years ago
This is Matrix for pre calc
gavmur [86]

The given system of equations in augmented matrix form is

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\-6&1&2&4&-12\\1&-3&-3&5&-20\\-2&5&6&0&12\end{array}\right]

If you need to solve this, first get the matrix in RREF:

  • Add 2(row 1) to row 2, row 1 to -3(row 3), and 2(row 1) to 3(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&11&5&-13&37\\0&19&10&4&-10\end{array}\right]

  • Add 11(row 2) to -5(row 3), and 19(row 1) to -5(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&-164&132&-1052\end{array}\right]

  • Add 164(row 3) to -91(row 4):

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&13080&-39240\end{array}\right]

  • Multiply row 4 by 1/13080:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&153&-823\\0&0&0&1&-3\end{array}\right]

  • Add -153(row 4) to row 3:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&-91&0&-364\\0&0&0&1&-3\end{array}\right]

  • Multiply row 3 by -1/91:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&-6&8&-58\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add 6(row 3) and -8(row 4) to row 2:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&5&0&0&-10\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 2 by 1/5:

\left[\begin{array}{cccc|c}3&2&-4&2&-23\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Add -2(row 2), 4(row 3), and -2(row 4) to row 1:

\left[\begin{array}{cccc|c}3&0&0&0&3\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

  • Multiply row 1 by 1/3:

\left[\begin{array}{cccc|c}1&0&0&0&1\\0&1&0&0&-2\\0&0&1&0&4\\0&0&0&1&-3\end{array}\right]

So the solution to this system is (w,x,y,z)=(1,-2,4,-3).

6 0
3 years ago
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malfutka [58]
Between 2 and 3, after the 2 1/4 point, but before the halfway point.
5 0
3 years ago
A taxi driver had 29 fares to and from the airport last Monday. The price for a ride to the airport is $4.50, and the price for
Serhud [2]

Answer:(12,17)

Step-by-step explanation:

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5 0
3 years ago
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krek1111 [17]

Answer:

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Step-by-step explanation:

8 0
2 years ago
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