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Olenka [21]
3 years ago
11

Prepare journal entries to record each of the following transactions of a merchandising company. The company uses a perpetual in

ventory system and the gross method.
Nov. 5 Purchased 900 units of product at a cost of $10 per unit. Terms of the sale are 4/10, n/60; the invoice is dated November 5.
Nov. 7 Returned 35 defective units from the November 5 purchase and received full credit.
Nov. 15 Paid the amount due from the November 5 purchase, minus the return on November 7.
Business
1 answer:
k0ka [10]3 years ago
8 0

Answer:

Nov 05

Dr Merchandise inventory 9,000

Cr Accounts payable 9,000

Nov 07

Dr Accounts payable 350

Cr Merchandise inventory 350

Nov 15

Dr Accounts payable 8,650

Cr Merchandise inventory 346

Cr Cash 8,304

Explanation:

Preparation of Journal entries

Based on the information given we were told that on Nov. 5 the company Purchased 900 units of product at the amount of $10 per unit which means that the Journal entry will be:

Nov 05

Dr Merchandise inventory 9,000

Cr Accounts payable 9,000

(900 units *$10 per units)

Based on the information given we were told that the company on Nov. 7 Returned 35 defective units from the the month of November 5 purchase in which they received full credit which means that the Journal entry will be:

Nov 07

Dr Accounts payable 350

Cr Merchandise inventory 350

(35*$10 per units)

Based on the information given we were told that the company on Nov. 15 Paid the amount of money due from the month of November 5 purchase in which they minus the return on November 7 which means that the Journal entry will be:

Nov 15

Dr Accounts payable 8,650

(9,000- 350)

Cr Merchandise inventory 346

(4%*8,650)

Cr Cash 8,304

(8,650-346)

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Answer and Explanation:

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Given that :

Repair time, including travel time =  mean of 1.6 hours per call.

Requests for copier repairs = mean rate of 2.1 per eight-hour day

i.e mean rate R = 2.1/day

Time = 8 hours

thus; mean rate μ = 8 hours/ 1.6 hours = 5

(a)

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I_i = \dfrac{R^2}{\mu (\mu-R)}

I_i = \dfrac{2.1^2}{5 (5-2.1)}

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I_i = \dfrac{4.41}{14.5}

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The system utilization is determined as follows:

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where;

P₀ = 0.58

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