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Shalnov [3]
3 years ago
12

Subtract (8x – 2) – (5х – 7)

Mathematics
2 answers:
professor190 [17]3 years ago
7 0

Answer: 3x - 9

Step-by-step-explanation: To solve the expression (8x – 2) – (5х – 7) we will be using properties of operations. First, use the commutative and associative properties to move the values next to each other to combine like terms.

(8x – 2) – (5х – 7)

(8x-5x)+(-2-7)

3x-9

So, the subtracted answer is 3x - 9

Vadim26 [7]3 years ago
7 0

Answer:

the answer is 3x+5

Step-by-step explanation: you keep 8x-2 and distribute the negative to 5x-7. which leaves you with 8x-2-5x+7 and then you combine like terms and get 3x+5

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What is the value of the expression 6x - y when x = 3 and y = 1? (5 points)
Vladimir [108]

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the answer is 17

Step-by-step explanation:

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3 years ago
according to the fundemental theorem of algebra, how many roots exist for the polynomial function? f(x) = (x^3-3x+1)^2
Svetradugi [14.3K]

Answer:

6

Step-by-step explanation:

First, we can expand the function to get its expanded form and to figure out what degree it is. For a polynomial function with one variable, the degree is the largest exponent value (once fully expanded/simplified) of the entire function that is connected to a variable. For example, x²+1 has a degree of 2, as 2 is the largest exponent value connected to a variable. Similarly, x³+2^5 has a degree of 2 as 5 is not an exponent value connected to a variable.

Expanding, we get

(x³-3x+1)²  = (x³-3x+1)(x³-3x+1)

= x^6 - 3x^4 +x³ - 3x^4 +9x²-3x + x³-3x+1

= x^6 - 6x^4 + 2x³ +9x²-6x + 1

In this function, the largest exponential value connected to the variable, x, is 6. Therefore, this is to the 6th degree. The fundamental theorem of algebra states that a polynomial of degree n has n roots, and as this is of degree 6, this has 6 roots

3 0
3 years ago
A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co
butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

\displaystyle \vec{v}=\frac{\vec{x}}{t}

Where \vec x is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

\displaystyle \vec{x}=\vec{v}.t

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

\displaystyle \vec{v_1}=

\displaystyle \vec{v_1}=\ km/h

The displacement of the plane in 2 hours is

\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)

\displaystyle \vec{x_1}=km

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

\displaystyle \vec{v_2}=

\displaystyle \vec{v_2}=km/h

The displacement in 1 hour is

\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)

\displaystyle \vec{x_2}=km

The total displacement is the vector sum of both

\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+

\displaystyle \vec{x_t}=km

\displaystyle \vec{x_t}=

The distance from the airport is the module of the displacement:

\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}

\displaystyle |\vec{x_t}|=894.43\ km

8 0
3 years ago
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