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2 years ago

12

I don't get this problem

2 answers:

svetoff [14.1K]2 years ago

7 0

First, you would put 4 as the numerator, because the silk butterfly's wingspan is 4 cm. Then, you would put 20 as the denominator, because the butterfly's wingspan is 20 cm. Now we have 4/20, which simplifies to 1/5 (the GCF of 4 and 20 is 4, so 4 divided by 4 = 1 and 20 divided by 4 = 5). Therefore, you answer would be 1/5.

Dominik [7]2 years ago

4 0

20/4.... 5cm is ur answer

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Find the area of the surface. The part of the surface z = xy that lies within the cylinder x2 + y2 = 36.

rewona [7]

Answer:

Step-by-step explanation:

From the given information:

The domain D of integration in polar coordinates can be represented by:

D = {(r,θ)| 0 ≤ r ≤ 6, 0 ≤ θ ≤ 2π) &;

The partial derivates for z = xy can be expressed as:

$y =\dfrac{\partial z}{\partial x} , x = \dfrac{\partial z}{\partial y}$

Thus, the area of the surface is as follows:

$\iint_D \sqrt{(\dfrac{\partial z}{\partial x})^2+ (\dfrac{\partial z}{\partial y})^2 +1 }\ dA = \iint_D \sqrt{(y)^2+(x)^2+1 } \ dA$

$= \iint_D \sqrt{x^2 +y^2 +1 } \ dA$

$= \int^{2 \pi}_{0} \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr \ d \theta$

$=2 \pi \int^{6}_{0} \ r \sqrt{r^2 +1 } \ dr$

$= 2 \pi \begin {bmatrix} \dfrac{1}{3}(r^2 +1) ^{^\dfrac{3}{2}} \end {bmatrix}^6_0$

$= 2 \pi \times \dfrac{1}{3} \Bigg [ (37)^{3/2} - 1 \Bigg]$

$= \dfrac{2 \pi}{3} \Bigg [37 \sqrt{37} -1 \Bigg ]$

3 0

2 years ago

What is the quotient of 3 divided 1/6<br>

Bess [88]

Answer:

To find the quotient of 3 divided by 1/6 you must multiply by the reciprocal of the fraction, in this case it is 6.

So you would rewrite it as,

3*6=18

So your answer is multiply 3 by 6.

P.S * represents multiplication.

Step-by-step explanation:

5 0

2 years ago

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morpeh [17]

3n + 21 is the answer

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1 year ago

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AfilCa [17]

Answer:

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Step-by-step explanation:

This seems to be a Chihuahua breed of a dog

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madreJ [45]

Integer??? Idk I'm sorry....

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