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zloy xaker [14]
2 years ago
9

Does anyone know the middle question: WILL MARK BRAINLIEST Options Xyz 2xyz 3xyz

Mathematics
2 answers:
sveta [45]2 years ago
6 0

Using the formula's, you can find out the answer:

Rectangular Prism- LWH

Pyramid- XYZ/3

1. Make up numbers for the Variables: X=6, Y=3, Z=8

2. Find the volume for the Rectangular Prism: 6 x 3 x 8 = 144

3. Find the Volume for the Pyramid: 6 x 3 x 24 = 432 (Because there is a times 3 there), then, divide by 3, because to find the Volume, you need to divide by 3, to get 144.

Hope this helped. If you need a more detailed Explanation, comment and I'll add to this!

vovangra [49]2 years ago
3 0

Answer:

volume of prism- XYZ

Volume of the pyramid - 3XYZ

Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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P(X< ) 1-P(X> ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
Mashutka [201]

Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

Binomial probability distribution

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The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 30, p = 0.626

So

\mu = E(X) = np = 30*0.626 = 18.78

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{30*0.626*0.374} = 2.65

What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

7 0
3 years ago
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Answer:

y =  45/m^2  −  49/4

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3 years ago
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Step-by-step explanation:

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6 0
3 years ago
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7 0
2 years ago
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