Hydrogen makes stars and stars spend most of their lifetime making helium.
The heavier elements are made when an old-age, high mass star explodes as a nova or supernova and then dies.
Answer:
4.7 m³
Explanation:
We'll use the gas law P1 • V1 / T1 = P2 • V2 / T2
* Givens :
P1 = 101 kPa , V1 = 2 m³ , T1 = 300.15 K , P2 = 40 kPa , T2 = 283.15 K
( We must always convert the temperature unit to Kelvin "K")
* What we want to find :
V2 = ?
* Solution :
101 × 2 / 300.15 = 40 × V2 / 283.15
V2 × 40 / 283.15 ≈ 0.67
V2 = 0.67 × 283.15 / 40
V2 ≈ 4.7 m³
Answer:
42.05 m/s
Explanation:
From the question given above, the following data were obtained:
Initial velocity (u) = 0 m/s
Height (h) = 239 m
Acceleration due to gravity (g) = 3.7 m/s²
Final velocity (v) =?
The velocity with which the camera hits the ground can be obtained as follow:
v² = u² + 2gh
v² = 0² + 2 × 3.7 × 239
v² = 0 + 1768.6
v² = 1768.6
Take the square root of both side
v = √(1768.6)
v = 42.05 m/s
Therefore, the velocity with which the camera hits the ground is 42.05 m/s
First, we need to calculate for the height where the mailbag
was dropped.
h = 3.50 * t^3
at t = 1.75 s, h is:
h = 3.50 * (1.75)^3
h = 18.758 m
Then we can use the equation to solve for time:
h = v0t + 0.5gt^2
where v0 is initial velocity = 0, t = time, g =
acceleration due to gravity
18.758 m = 0 + 0.5 * (9.81 m/s^2) * t^2
t^2 = 3.8242
t = 1.96 s
<span>So the mailbag reaches the ground after 1.96 seconds</span>
