Answer:
d=1.25 m
Explanation:
fd=.5mv2-.5mv1; 10(d)=.5(50)(.5)-0; 10(d)=12.5; d=12.5/10; d=1.25 m
Answer:
b. B, A, C
Explanation:
To solve this problem, let us find the net forces they are experiencing.
Net force = mass x acceleration
Object A; mass = 8kg and acceleration = 4m/s²
Net force = 8 x 4 = 32N
Object B; mass = 10kg and acceleration = 3m/s²
Net force = 10 x 3 = 30N
Object C: mass = 7kg and acceleration = 5m/s²
Net force = 7 x 5 = 35N
So, increasing order of their net force;
B < A < C
Answer:
The acceleration of the car will be 
Explanation:
We have given that distance from stop sign s = 200 m
Time t = 0.2 sec
We have to find the constant acceleration
Now from second equation of motion 


So the acceleration of the car will be 
The particle has an acceleration vector with one component directed toward the center of its orbit, and the other directing tangentially to its orbit. Call these components
(
for center) and
(
for tangent). Then its acceleration vector has magnitude

We have

where
is the particle's speed and
is the radius of orbit, so

We're given that the particle's speed changes at a rate of 23.1 m/s^2. Its velocity vector points in the same direction as
, i.e. perpendicular to
, so

Then the magnitude of the particle's acceleration is

Work = force × distance
= 35 N × 200 m
= 7000 J