The period of a pendulum is directly proportional to the mass of the bob. true or false.
1 answer:
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Answer:
Acceleration will be
So option (D) will be correct answer
Explanation:
We have given angular speed of the electrical motor
We have to change this angular speed in rad/sec for further calculation
So
Armature radius is given r = 7.165 cm = 0.07165 m
We have to find the acceleration of edge of motor
Acceleration is given by
So acceleration will be
So option (D) will be correct answer
Answer:
τ = 32.8635 N-m (counterclockwise)
Explanation:
Given
M = 2 kg
L = 2 m
r = 0.10 m
m₁ = 4 kg
r₁ = (1.00-0.30)m = 0.70 m
m₂ = 5 Kg
r₂ = (0.90-0.75)m = 0.15 m
In order to determine the torque on the meterstick if it is received and allowed to pivot about the 90 cm mark (ypu can see the pic to understand the question), we apply:
τ = r₁*m₁*g + r₂*m₂*g - r*M*g = g*(r₁*m₁+r₂*m₂-r*M)
⇒ τ = (9.81 m/s²)(0.70 m*4 kg + 0.15 m*5 Kg - 0.10 m*2 kg)
⇒ τ = 32.8635 N-m (counterclockwise)
