Answer:
proof in explanation
Explanation:
First, we will calculate the number of half-lives:
![n = \frac{t}{t_{1/2}}](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7Bt%7D%7Bt_%7B1%2F2%7D%7D)
where,
n = no. of half-lives = ?
t = total time passed = 2100 million years
= half-life = 700 million years
Therefore,
![n = \frac{2100\ million\ years}{700\ million\ years}\\\\n = 3](https://tex.z-dn.net/?f=n%20%3D%20%5Cfrac%7B2100%5C%20million%5C%20years%7D%7B700%5C%20million%5C%20years%7D%5C%5C%5C%5Cn%20%3D%203)
Now, we will calculate the number of uranium nuclei left (
):
![n_u = \frac{1}{2^{n} }(total\ nuclei)\\\\n_u = \frac{1}{2^{3} }(6400\ million)\\\\n_u = \frac{1}{8}(6400\ million)\\\\n_u = 800\ million](https://tex.z-dn.net/?f=n_u%20%3D%20%5Cfrac%7B1%7D%7B2%5E%7Bn%7D%20%7D%28total%5C%20nuclei%29%5C%5C%5C%5Cn_u%20%3D%20%5Cfrac%7B1%7D%7B2%5E%7B3%7D%20%7D%286400%5C%20million%29%5C%5C%5C%5Cn_u%20%3D%20%5Cfrac%7B1%7D%7B8%7D%286400%5C%20million%29%5C%5C%5C%5Cn_u%20%3D%20%20800%5C%20million)
and the rest of the uranium nuclei will become thorium nuclei (
)
![n_{th} = total\ nuclei - n_u\\n_{th} = 6400\ million-800\ million\\n_{th} = 5600\ million](https://tex.z-dn.net/?f=n_%7Bth%7D%20%3D%20total%5C%20nuclei%20-%20n_u%5C%5Cn_%7Bth%7D%20%3D%206400%5C%20million-800%5C%20million%5C%5Cn_%7Bth%7D%20%3D%205600%5C%20million)
dividing both:
![\frac{n_{th}}{n_u}=\frac{5600\ million}{800\ million} \\\\n_{th} = 7n_u](https://tex.z-dn.net/?f=%5Cfrac%7Bn_%7Bth%7D%7D%7Bn_u%7D%3D%5Cfrac%7B5600%5C%20million%7D%7B800%5C%20million%7D%20%5C%5C%5C%5Cn_%7Bth%7D%20%3D%207n_u)
<u>Hence, it is proven that after 2100 million years there are seven times more thorium nuclei than uranium nuclei in the rock.</u>
If the soloist produces "x" decibels and the 10-person choir produces "y" decibels, combined they will produce "x+y" decibels.
The second choir has 90 additional singers, we base our description on the first choir. If a 10-person choir produces "x+y" decibels, then the 90 person choir produces 10 (x+y) decibels.
Answer:
Total impulse =
= Initial momentum of the car
Explanation:
Let the mass of the car be 'm' kg moving with a velocity 'v' m/s.
The final velocity of the car is 0 m/s as it is brought to rest.
Impulse is equal to the product of constant force applied to an object for a very small interval. Impulse is also calculated as the total change in the linear momentum of an object during the given time interval.
The magnitude of impulse is the absolute value of the change in momentum.
![|J|=|p_f-p_i|](https://tex.z-dn.net/?f=%7CJ%7C%3D%7Cp_f-p_i%7C)
Momentum of an object is equal to the product of its mass and velocity.
So, the initial momentum of the car is given as:
![p_i=mv](https://tex.z-dn.net/?f=p_i%3Dmv)
The final momentum of the car is given as:
![p_f=m(0)=0](https://tex.z-dn.net/?f=p_f%3Dm%280%29%3D0)
Therefore, the impulse is given as:
![|J|=|p_f-p_i|=|0-mv|=|-mv|=mv](https://tex.z-dn.net/?f=%7CJ%7C%3D%7Cp_f-p_i%7C%3D%7C0-mv%7C%3D%7C-mv%7C%3Dmv)
Hence, the magnitude of the impulse applied to the car to bring it to rest is equal to the initial momentum of the car.
'C' is a simple explanation of astigmatism.
Answer:
B train!
Explanation:
A train travelled at 40 km/hr. (120/3)
B train traveled at 45 km/hr (180/4)