(x-8) ^ 2 = 121
(x-8) = + / - root (121)
x = 8 +/- root (121)
The solutions are:
x1 = 8 + root (121)
x2 = 8 - root (121)
2a ^ 2 = 8a-6
2a ^ 2-8a + 6 = 0
a ^ 2-4a + 3 = 0
(a-1) (a-3) = 0
The solutions are:
a1 = 1
a2 = 3
x ^ 2 + 12x + 36 = 4
x ^ 2 + 12x + 36-4 = 0
x ^ 2 + 12x + 32 = 0
(x + 4) (x + 8) = 0
The solutions are:
x1 = -8
x2 = -4
x ^ 2-x + 30 = 0
x = (- b +/- root (b ^ 2 - 4 * a * c)) / 2 * a
x = (- (- 1) +/- root ((- 1) ^ 2 - 4 * (1) * (30))) / 2 * (1)
x = (1 +/- root (1 - 120))) / 2
x = (1 +/- root (-119))) / 2
x = (1 +/- root (119) * i)) / 2
The solutions are:
x1 = (1 + root (119) * i)) / 2
x2 = (1 - root (119) * i)) / 2
4, 8, 12, 16 I can’t see your table but I think these are the answers. :)
The greatest common factor of two numbers, one of which is 1, will always be 1.
Answer: the company should invest $12191 each week
Step-by-step explanation:
The amount that the company needs is $5,400,000
We would apply the periodic interest rate formula which is expressed as
P = a/[{(1+r)^n]-1}/{r(1+r)^n}]
Where
P represents the weekly payments.
a represents the amount that the company needs
r represents the rate.
n represents number of weekly payments. Therefore
a = 5,400000
There are 52 weeks in a year
r = 0.079/52 = 0.0015
n = 52 × 14 = 728
Therefore,
P = 5400000/[{(1+0.0015)^728]-1}/{0.0015(1+0.0015)^728}]
5400000/[{(1.0015)^728]-1}/{0.0015(1.0015)^728}]
P = 5400000/{2.98 -1}/[0.0015(2.98)]
P = 5400000/(1.98/0.00447)
P = 5400000/442.95
P = $12191
62.50/5=12.50 for each tour
500/12.50 = 40 tours
