Digestive. This also includes the intestines.
The question is incomplete, the complete question is;
Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to be more acidic in aqueous solution than H2S , e.g. have a larger Ka.
Answer:
H2Se
Explanation:
The acidity and extent of acid dissociation (shown by Ka value) depends on the nature of the bond between hydrogen and the group 6A element.
If we compare the H-S bond and the H-Se bond, we will discover that the H-Se bond is longer, weaker and breaks more easily than the H-S bond. As a result of this, H2Se is more acidic than H2S.
Answer:
B.
Explanation:
Buffer has equal concentrations of A- and HA.
B. when [F -] is equal to [HF]
Answer:
Break up the soil to increase the number of pores should be your answer.
Explanation:
If you do that it will increase the amount of water in the plant.
Answer:
pH = 9,32
Explanation:
The compound with 2 ionizable groups has the following equilibriums:
H₂M ⇄ HM⁻ + H⁺ pka = 6,2
HM⁻ ⇄ M²⁻ + H⁺ pka = 9,5
The reaction of M²⁻ with HCl is:
M²⁻ + HCl → HM⁻ + Cl⁻
The moles of M²⁻ are:
0,100L×1,0M = 0,1moles
And moles of HCl are:
0,060L×1,0M = 0,06moles
That means that moles of M²⁻ will be 0,1-0,06 = 0,04mol and moles of HM⁻ will be the same than HCl, 0,06mol
Using Henderson-Hasselbalch formula:
pH = pka + log₁₀ [M²⁻] / [HM⁻]
Replacing:
pH = 9,5 + log₁₀ [0,04] / [0,06]
<em>pH = 9,32</em>
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I hope it helps!
