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3 years ago

Consider the following equilibrium:

Chemistry

2 answers:

balu736 [363]3 years ago

8 0

Answer:

see explanataion

Explanation:

Buffer solutions are defined as solutions containing a weak electrolyte (wk acid or wk base) and the salt of the weak electrolyte.

Given HF(aq) + H₂O(l) ⇄ H₃O(l) + F⁻, a buffer solution would result from a solution composition when [F -] is equal to [HF]. Such is commonly referred to as a 50/50 buffer as the acid and salt are in equal concentrations. However, a buffer solution still will exist even if the concentrations of acid and salt are not equal. The presence of the weak acid or weak base and the salt of the electrolytes is the only requirement.

Veseljchak [2.6K]3 years ago

3 0

Answer:

Explanation:

Buffer has equal concentrations of A- and HA.

B. when [F -] is equal to [HF]

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An ion always has a ________ or ________ charge. While a covalent bond always has no _________, meaning it is __________.

almond37 [142]

An ion has a positive or negative charge. While a covalent bond always has no charge, meaning it is neutral.

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4 years ago

A solution was prepared by dissolving 2.2 g of an unknown solute in 16.7 g of CCl4. A thermal analysis was performed for this so

laila [671]

Answer:

Molar mass of unknown solute is 679 g/mol

Explanation:

Let us assume that the solute is a non-electrolyte.

For a solution with non-electrolyte solute remains dissolved in it -

Depression in freezing point of solution, $\Delta T_{f}=K_{f}.m$

where, m is molality of solute in solution and $K_{f}$ is cryogenoscopic constant of solvent.

Here $\Delta T_{f}=(-22.9^{0}\textrm{C})-(-28.7^{0}\textrm{C})=5.8^{0}\textrm{C}$

If molar mass of unknown solute is M g/mol then-

$m=\frac{\frac{2.2}{M}}{0.0167}mol/kg$

So, $5.8^{0}\textrm{C}=29.9^{0}\textrm{C}/(mol/kg)\times \frac{\frac{2.2g}{M}}{0.0167}mol/kg$

so, M = 679 g/mol

4 0

3 years ago

What is the percent mass oxygen in calcium carbonate (CaCo3)?

Gnoma [55]

<span>Step 1 is to determine the mass of each part
Mass of Ca is 40.08 g
Mass of C is 12.01 g
Mass of O is 16.00 x 3 = 48.00 g
Step 2 is to determine the total mass of the compound
Total mass of CaCO3 is 40.08 + 12.01 + 48.00 = 100.09 g

Step 3 is to determine the % of each part using the following formula:
Mass of part / total mass x 100 =

40.08 / 100.09 x 100 = 40.04 % Ca

12.01 / 100.09 x 100 = 12.00 % C

48.00 / 100.09 x 100 = 47.96 % O

Step 4 is to double check by adding all percentages. If they equal 100, then I probably did it right. :)
40.04
+12.00
+47.96
=100.00</span><span>
</span>

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3 years ago

Read 2 more answers

PLEASE HELPPPPP!!!!!!!

marin [14]

Boiling water is a physical change, because it is changing state of matter, there is a controllable temperature change, and you can change it back.

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4 years ago

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Afina-wow [57]

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