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iVinArrow [24]
3 years ago
15

Which of he following statements describes a limitation of the food web model?

Chemistry
1 answer:
Hunter-Best [27]3 years ago
4 0

Answer:

nothing

Explanation:

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Read the descriptions below of two substances and an experiment on each. Decide whether the result of the experiment tells you t
marissa [1.9K]

Answer:

Sample A is a mixture

Sample B is a mixture

Explanation:

For sample A, we are told that the originally yellow solid was dissolved and we obtained an orange powder at the bottom of the beaker. Subsequently, only about 30.0 g of solid was recovered out of the 50.0g of solid dissolved. This implies that the solid is not pure and must be a mixture. The other components of the mixture must have remained in solution accounting for the loss in mass of solid obtained.

For sample B, we are told that boiling started at 66.2°C and continued until 76.0°C. The implication of this is that B must be a mixture since it boils over a range of temperatures. Pure substances have a sharp boiling point.

7 0
2 years ago
A gas has a volume of 1.75L at -23C and 150.0kPa. At what temperature would the gas occupy 1.30L at 210.0kPa?
Katen [24]

Answer:

T2 = 260 K  

Explanation:

<em>Given data:</em>

P1 = 150.0 k Pa

T1 = (-23+ 273.15) K = 250.15 K  

V1 = 1.75 L  

P2 = 210.0 kPa  

V2 = 1.30 L

<em>To find:</em>

T2 = ?

<em>Formula:</em>

\frac{P_1 V_1}{T_1} = \frac{P_2 V_2}{T_2}

T_2 = \frac{P_2 V_2 T_1}{P_1 V_1}

<em>Calculation:</em>

T2 = (210.0 kPa) x (1.30 L) x (250.15 K) / (150.0 kPa) x (1.75 L)

T2 = 260 K  

8 0
3 years ago
How many moles of nitrogen, N, are in 61.0 g of nitrous oxide, N2O?
Oksana_A [137]

Answer:

2.77 mol N

Explanation:

M(N2O) = 2*14 + 16 = 44 g/mol

61.0 g * 1 mol/44g = (61/44) mol N2O

                       N2O ---- 2N

                    1 mol         2 mol

            (61/44) mol        x mol

x = (61/44)*2/1 = 2.77 mol N

4 0
3 years ago
Which of the following elements will form a positive ions? check all that apply
tamaranim1 [39]

we're the rest of the question

3 0
3 years ago
How well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure
Phoenix [80]

Answer:

As temperature increases the volume of given amount of gas increases while pressure and number of moles remain constant.

Explanation:

According to the charle's law,

The volume of given amount of gas is directly proportional to the temperature at constant pressure and number of moles of gas.

Mathematical expression:

V ∝ T

V = KT

V/T = K

When temperature changes from T₁ to T₂ and volume changes from V₁ to V₂.

V₁/T₁ = K        V₂/T₂ = K

or

V₁/T₁  = V₂/T₂

Thus, the ratio of volume and temperature remain constant for constant amount of gas at constant pressure.

6 0
3 years ago
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