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lions [1.4K]
3 years ago
11

The molar heat of fusion for water is 6. 01 kJ/mol. How much energy is released when 36. 8 g of water freezes at its freezing po

int? Use q equals n delta H. 6. 12 kJ 12. 3 kJ 108 kJ 221 kJ.
Chemistry
1 answer:
kondaur [170]3 years ago
4 0

Answer: The correct option is, (B) 12.3 KJ

Solution :

First we have to calculate the moles of water.

Now we have to calculate the amount of heat released.

Formula used :

where,

q = heat released

n = number of moles = 2.04 mole

= molar enthalpy of fusion of a substance = -6.01 KJ/mole

Now put all the give values in the above formula, we get the amount of heat released.

The negative sign indicate heat released.

Therefore, the amount of heat released is, 12.3 KJ

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We have to solve this question using the stoichiometry of the reaction:

The equation of the reaction is;

2 C12H26(l) + 37 O2(g) -----> 24 CO2(g) + 26 H2O(l) + 15,026 kJ

According to the question;

Number of moles of CO2 released = 21.3 g/44 g/mol = 0.48 moles

From the  stoichiometry of the reaction:

Since;

24 moles of CO2 released 15,026 KJ

0.48 moles of CO2 will release 0.48 * 15,026/24

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Answer:

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Cold water is denser than hot water:

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