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lara31 [8.8K]
3 years ago
15

CAN SOMEONE PLEASE HELP ME WITH MY PHYSICS QUESTIONS? I NEED CORRECT ANSWERS ONLY!

Physics
2 answers:
notka56 [123]3 years ago
7 0

ok i can help you what are your questions

ankoles [38]3 years ago
4 0

i can help if i know them(:

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Jacki evaluated the expression below. 2 cubed (3 minus 1) + 4 (8 minus 12) = 2 cubed (2) + 4 (4) = 8 (2) + 16 = 16 + 16 = 32. Wh
Naddika [18.5K]

Answer:

Her error was that she did not subtract 12 from 8 correctly

Explanation:

Jackie did 8-12 instead of 12-8

8 0
3 years ago
What derived unit is used to measure the slope of the line in this graph?
vlabodo [156]

Answer:

C. g/cm³

Explanation:

The slope is measured by calculating the variation of the Y values over the X values between two points on a line.  

So, the formula is: Slope = Δy/Δx

That means that we also take the units.

In this case, the Y-axis unit is in g, while the X-axis unit is in cm³.

Dividing a Y-variation over an X-variation will give you g/cm³.

In this case, let's assume the line passes through (10,100) (not exactly, but close enough for the example), and it passes through (0,0)

So the slope would be: (100-0) g / (10-0) cm³ = 10 g/cm³

3 0
4 years ago
Usa test prep- Look at the picture below to answer. If u answer correctly i will mark you as brainliest!
Vladimir [108]

Answer:

A

Explanation:

The greatest concentration of atomic mass is in the nucleus because it is made up of protons and neutrons. The electrons surrounding the nucleus don't have as much mass as protons or neutrons.

Hopefully this helps...

4 0
3 years ago
Read 2 more answers
Buna!! ne pune le fizica intrebari despre legarea mixta!! Va rog , ma puteti ajuta ?? Ptr raspunsuri bune dau coroana!!!!!!
Iteru [2.4K]
<span>Un solid covalent de rețea constă din atomi reținuți împreună de o rețea de legături covalente (perechi de electroni împărțite între atomi de electronegativitate similară) și, prin urmare, pot fi considerați o singură moleculă mare.     </span>
4 0
3 years ago
Calculate the minimum amount of energy, in joules, required to completely melt 145 g of silver initially at 22.0°C. The melting
Tcecarenko [31]

Answer:

47391.8 J

Explanation:

Q = m c Δt

For melting, Δt = (962-22)°C

Heat required to attain melting point = 145 x 10 ⁻³ x 236 x 940 =

= 32166.8 J

Heat required to melt at melting point = m L , L is latent heat of fusion.

= 145 x 10⁻³ x 105 x 10³ = 15225 J

Total energy required = 47391.8 J

6 0
4 years ago
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