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1 year ago

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two mass Ma=2kg and Mb=5kg on incline are connected together by string as shown below the coefficient of kinetic friction betwee

n each mass and it's incline is 0.3 if Ma move up and Mb move down determine. (1) the tension in the connecting string. (2)their acceleration

1 answer:

aniked [119]1 year ago

5 0

Answer:

yourjejejrjrjrjr mother

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Explanation:

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2 years ago

A toaster uses 6700 joules of energy in 45 seconds to toast to a piece of bread what is power of the oven

just olya [345]

P= w/t and W= Work
In this case, W= 6,700j, and T= 45 seconds
Power is the ratio of work per unit time. When you perform a work in a given span of time, the ratio of work performed with respect to time is Called Power.
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so, P= 6,700/45
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2 years ago

If the angular velocity of the pully is -8.4rad/s at a given time, and its anglar acceleration is -2.8rad/s2, what is the angula

snow_lady [41]

Here we know that

$\omega_i = - 8.4 rad/s$

$\alpha = - 2.8 rad/s^2$

$t = 1.5 s$

now from kinematics we have

$\omega_f = \omega_i + \alpha t$

now from above all values we have

$\omega_f = (-8.4 rad/s) + (-2.8 rad/s^2)(1.5)$

$\omega_f = -8.4 + (-4.2)$

$\omega_f = -12.6 rad/s$

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6 0

2 years ago

Which of the following could be classified as a problem that could be answered with a technological design?

loris [4]

I think the answer is 4) All of the above!! :)

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3 years ago

Suppose an electrical wire is replaced with one having every linear dimension doubled (i.e. the length and radius have twice the

saul85 [17]

Answer:

The wire now has less (the half resistance) than before.

Explanation:

The resistance in a wire is calculated as:

$R=\alpha \frac{l}{s}$

Were:

R is resistance

$\alpha$ is the resistance coefficient

l is the length of the material

s is the area of the transversal wire, in the case of wire will be circular area ( $s=\pi r^{2}$ ).

So if the lenght and radius are doubled, the equation goes as follows:

$R=\alpha \frac{l}{\pi r^{2} } =\alpha \frac{2l}{\pi {(2r)}^{2} } =\alpha \frac{2l}{\pi 4 {r}^{2} }=\frac{1}{2} \alpha \frac{l}{\pi r^{2} }$

So finally because the circular area is a square function, the resulting equation is half of the one before.

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2 years ago