W = F x d
F: 450 N
d = 10 m
plug your variables into the equation to get W = 450N x 10m
Answer:
(a) The x-component of velocity is 31.55 km/h
(b) The y-component of velocity is 44.92 km/hr
Solution:
As per the solution:
The relative position of ship A relative to ship B is 4.2 km north and 2.7 km east.
Velocity of ship A,
= 22 km/h towards South = 
Velocity of ship B,
= 39 km/h Towards North east at an angle of
= 
Now, the velocity of ship A relative to ship B:



Now,


I believe it's frequency.
Answer:
A. 216.36 
B. 96.56 
Explanation:
Let
be the distance in first part.
= velocity × time
= 85 × 
= 49.58 km
Let
be the distance in first part.
= 130 km
Average velocity = 
When second leg of the trip is
A. Toward north
Average velocity =
}{Total time} [/tex]
Average velocity = 
Average velocity =216.36 
B. Toward south
Average velocity =
}{Total time} [/tex]
Average velocity = 
Average velocity =96.56 
f = 10000N
distance moved = 20 m
work done = 10000*20 = 200000