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3 years ago

5

A coil has N turns enclosing an area of A. In a physics laboratory experiment, the coil is rotated during the time interval Δt f

rom a position in which the plane of each turn is perpendicular to Earth's magnetic field to one in which the plane of each turn is parallel to the field. The magnitude of Earth's magnetic field at the lab location is B. Part A What is the magnitude Φinitial of the magnetic flux through one turn of the coil before it is rotated?

1 answer:

anzhelika [568]3 years ago

6 0

Answer:

$\phi_i = BA$

Explanation:

magnetic flux is the count of magnetic field lines passing through a given loop or area

As we know that magnetic flux is given by the formula

$\phi = \vec B. \vec A$

here we also know that magnetic field B and plane of the coil is perpendicular in initial position

So the area vector is always perpendicular to the plane of the coil

so the angle between magnetic field and area vector is parallel to each other and this angle would be zero

so magnetic flux of the coil initially we have

$\phi = BAcos0 = BA$

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two plane mirrors inclined at an angle of 50 degree to each othe r a ray is incident on mirror1 then thedeviation x of ray after

Kipish [7]

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3 years ago

If two conductors are not touching but are close to each other, a large enough voltage will cause an _________________ to occur

Aleks [24]

Answer:

Electrical breakdown.

Explanation:

When two conductors are relatively close enough, and have a very large voltage between them, it can lead to a Dielectric breakdown. A dielectric breakdown occurs when an insulator is subjected to a high enough voltage, suddenly becomes an electrical conductor and electric current flows through it. The air between the conductors is the insulator that breaks down, leading to an electrical discharge arc to flow between the two conductors. This electrical breakdown can cause catastrophic failure of electrical equipment, and fire hazards.

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3 years ago

A series AC circuit contains a resistor, an inductor of 150 mH, a capacitor of 5.00 mF, and a generator with DVmax 5 240 V opera

yanalaym [24]

Given:

Inductance, L = 150 mH

Capacitance, C = 5.00 mF

$\Delta V_{max}$ = 240 V

frequency, f = 50Hz

$I_{max}$ = 100 mA

Solution:

To calculate the parameters of the given circuit series RLC circuit:

angular frequency, $\omega$ = $2\pi f = 2\pi \times50 = 100\pi$

a). Inductive reactance, $X_{L}$ is given by:

$\X_{L} = \omega L = 100\pi \times 150\times 10^{-3} = 47.12\Omega$

$X_{L} = 47.12\Omega$

b). The capacitive reactance, $X_{C}$ is given by:

$\X_{C} = \frac{1}{\omega C} = \frac{1}{2\pi fC} = \frac{1}{2\pi \times 50\times 5.00\times 10^{-3}} = 0.636\Omega$

$X_{C} = 0.636\Omega$

c). Impedance, Z = $\frac{\Delta V_{max}}{I_{max}} = \frac{240}{100\times 10^{-3}} = 2400\Omega$

$Z = 2400\Omega$

d). Resistance, R is given by:

$Z = \sqrt {R^{2} + (X_{L} - X_{C})}$

$2400^{2} = R^{2} + (47.12 - 0.636)^{2}$

$R = \sqrt {5757839.238}$

$R = 2399.5\Omega$

e). Phase angle between current and the generator voltage is given by:

$tan\phi = \frac{X_{L} - X_{C}}{R}$

$\phi =tan^{-1}( \frac{X_{L} - X_{C}}{R})$

$\phi =tan^{-1}( \frac{47.12 - 0.636}{2399.5}) = tan^{-1}{0.0.01937}$

$\phi = 1.11^{\circ}$

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Arte-miy333 [17]

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3 years ago

2) What must be connected for an electrical current to flow in a simple current?

hjlf

2) What must be connected for an electrical current to flow in a simple current?

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5)What is the purpose of a load in a circuit?

<em>c.provide resistance to keep the voltage strong </em>

Load will provide the resistance to the circuit and help to build the voltage across it

6) What cause an electric current from a generator

<em>d.Magnets and conducting wires move near each other </em>

here when magnets move near wires then it will induce the electric current and behaves like generators

7) What do all generators have in common

<em>b.they transform mechanical into electrical energy </em>

They have magnets and rotating coils which will convert magnetic energy to electrical energy

8) How can we measure electrical current

<em>b.the pressure force is voltage;the # of electrons moving is amperes </em>

this voltage and number of electrons will help to calculate current

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2 years ago