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saveliy_v [14]
2 years ago
13

If you have a book to read that is 20 pages, and you have read 15% of the book, how many pages as you read?

Mathematics
1 answer:
marysya [2.9K]2 years ago
7 0

Answer:

3

Step-by-step explanation:

20*.15=3

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A lumber yard offers boards based on wood species, size, and grade. If a customer can choose among 3 species, 3 sizes, and 2 gra
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18

Step-by-step explanation:

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Hi can you help me ?
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2 years ago
At a 20th high school reunion, all the classmates were asked the number of children they had. The probability of having a partic
finlep [7]

Answer:

a) We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) P(C=0) = 0.05

d) For this case we see that the result from part b use the probability calculated from part c using the complement rule.

Step-by-step explanation:

For this case we have the following probability distribution given:

C    0        1        2         3       4       5        6       7        8      

P  0.05   0.14   0.34   0.24  0.11  0.07  0.02  0.02  0.01

And we assume the following questions:

a) Verify that this is a probability distribution

We need to check two conditions:

1) \sum_{i=1}^n P_i = 1

0.05+0.14+0.34+0.24+0.11+0.07+0.02+0.02+0.01= 1

2) P_i \geq 0 , \forall i=1,2,...,n

So we satisfy the two conditions so then we have a probability distribution

b) What is the probability one randonmly chosen classmate has at least one child

For this case we want this probability:

P(C \geq 1)

And we can use the complement rule and we got:

P(C \geq 1)= 1-P(C

c) What is the probability one randonmly chosen classmate has no children

For this case we want this probability:

P(C=0) = 0.05

d) Look at the answers for parts b and c and explain their relationship

For this case we see that the result from part b use the probability calculated from part c using the complement rule.

5 0
3 years ago
A rectangle has a length of 14 yards less than 9 times its width. If the area of the rectangle is 6183 square yards, find the le
Jlenok [28]

Answer:

 l=238\ yards

Step-by-step explanation:

From the question we are told that:

Area of Rectangle A=6183

Equation of Length

 l=9w-14

Where

w=width\ of\ triangle

Generally the equation for Area of Rectangle is mathematically given by

 A=(9w-14)w

 A=9w^2-14w

 6183=9w^2-14w

 9w^2-14w-6183=0

 w=28

Therefore

 l=9(28)-14

 l=238\ yards

4 0
3 years ago
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