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4 years ago

HELP PLEASE THIS IS PRETTY EASY AND I'LL GIVE BRAINLIEST

Mathematics

1 answer:

aalyn [17]4 years ago

4 0

Answer:

So your answer would be C

Step-by-step explanation:

If you dilate something it is increasing so all you have to do is multiply it by 3 to get 225

Hope this helps =)

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What are the zeros of the function f(x) = x2 + 5x + 5 written in simplest radical form?

AnnyKZ [126]

Given the function f(x)=x^2+5x+5 , to get the zeros we solve using quadratic formula;
x=[-b(+or-) sqrt(b^2-4ac)]/(2a)
from our function;
a=1,b=5, c=5

thus,

x=[-5(+or-)sqrt(5^2-4*1*5)]/(2*1)
x=[-5(+or-)sqrt(25-20)]/2
x=[-5+/-sqrt(5)/2

The answer is option C

4 0

3 years ago

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If (x)=<br> X-2<br> and d(x) = x + 3, what is the domain of (cd)(x)?

Nata [24]

Answer:

Option (2)

Step-by-step explanation:

Given functions are,

c(x) = $\frac{5}{x-2}$

d(x) = x + 3

Equation of the composite function will be,

(cd)(x) = c(x) × d(x)

= $\frac{5}{(x-2)}\times (x+3)$

= $\frac{5(x+3)}{(x-2)}$

This function is defined only when denominator is not equal to zero.

(x - 2) ≠ 2

Therefore, for real numbers except x = 2 will be the domain of the composite function.

Option (2) will be the answer.

3 0

3 years ago

A polygon with points (-3, 3), (-3, 0), (3,0) and (6,3) reflects across the y-axis. Which is a point on the transformed polygon?

Aloiza [94]

Answer:

0,-3

Step-by-step explanation:

because its across it so it probbly dose not cam o it dose poloyn it

3 0

3 years ago

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If f(2) = 13 and f '(x) ≥ 2 for 2 ≤ x ≤ 7, how small can f(7) possibly be?

timofeeve [1]

Answer:

Step-by-step explanation:

We are given that

f(2)=13

$f'(x)\geq 2$

$2\leq x\leq 7$

We have to find the possible small value of f(7).

We know that

$f'(x)=\frac{f(b)-f(a)}{b-a}$

Using the formula

$f'(x)=\frac{f(7)-f(2)}{7-2}$

$f'(x)=\frac{f(7)-13}{5}$

We have

$f'(x)\geq 2$

$\frac{f(7)-13}{5}\geq 2$

$f(7)-13\geq 2\times 5$

$f(7)-13\geq 10$

$f(7)\geq 10+13$

$f(7)\geq 23$

The small value of f(7) can be 23.

3 0

3 years ago

What’s the inverse of y=4x^2-2

slavikrds [6]

Interchange the x and y and solve for the resulting y.
x = 4y^2 - 2
(x + 2) = 4y^2
(x + 2)/4 = y^2
+/- sqrt(x + 2)/2 = y

The graph of these two is below.

The original is in red
The inverse is in blue and green

8 0

3 years ago