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3 years ago

Write the equation in slope-intercept form. 2/3(6y+9)=3/5(15x-20)

1 answer:

5 0

$\frac{2}{3}(6y+9)=\frac{3}{5}(15x-20)\ \ \ | multiply\ by\ 15\\\\
10(6y+9)=9(15x-20)\\\\
60y+90=135x-180\ \ \ | subtract\ 90\\\\
60y=135x-270\ \ \ | divide\ by\ 60\\\\
Slope\ intercept\ form:\ y=2.25x-4.5$

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3 years ago

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Answer: B) Linear; it can be written as y = -3x-6

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3 years ago

What is the answer to this -3m=-9+-2m

ikadub [295]

1. Simplify -9 + -2m to -9 - 2m

-3m = -9 - 2m

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3 years ago

A financial advisor is analyzing a family's estate plan. The amount of money that the family has invested in different real esta

Pachacha [2.7K]

Answer:

The amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

Step-by-step explanation:

Let the random variable X represent the amount of money that the family has invested in different real estate properties.

The random variable X follows a Normal distribution with parameters μ = $225,000 and σ = $50,000.

It is provided that the family has invested in n = 10 different real estate properties.

Then the mean and standard deviation of amount of money that the family has invested in these 10 different real estate properties is:

$\mu_{\bar x}=\mu=\$225,000\\\\\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}=\frac{50000}{\sqrt{10}}=15811.39$

Now the lowest 80% of the amount invested can be represented as follows:

$P(\bar X$

The value of z is 0.84.

*Use a z-table.

Compute the value of the mean amount invested as follows:

$\bar x=\mu_{\bar x}+z\cdot \sigma_{\bar x}$

$=225000+(0.84\times 15811.39)\\\\=225000+13281.5676\\\\=238281.5676\\\\\approx 238281.57$

Thus, the amount of money separating the lowest 80% of the amount invested from the highest 20% in a sampling distribution of 10 of the family's real estate holdings is $238,281.57.

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