Ask question

Ask question

All categories

3 years ago

10

n the graph above, the coordinates of the vertices of quadrilateral QPRS are Q(2, 4), P(4, 4), R(3, 1), and S(1, 1). If quadrila

teral QPRS is reflected across the x-axis to create quadrilateral GHIJ, find the coordinates of point J. A. (–1, –1) B. (1, –1) C. (3, –1) D. (4, –4)

1 answer:

Svet_ta [14]3 years ago

3 0

Here, Reflection is across x - axis
so, the rule says: (x, y) → (x, -y)

Now, Coordinate of S is (1, 1)

Coordinate of it's Image (J) = (1, -1)

In short, Your Answer would be: Option B

Hope this helps!

You might be interested in

Solve the oblique triangle where side a has length 10 cm, side c has length 12 cm, and angle beta has measure thirty degrees. Ro

strojnjashka [21]

Answer:

The missing side is $B = 6.0\ cm$

The missing angles are $\alpha = 56.2$ and $\theta = 93.8$

Step-by-step explanation:

Given

$A = 10\ cm$

$C = 12\ cm$

$\beta = 30$

The implication of this question is to solve for the missing side and the two missing angles

Represent

Angle A with $\alpha$

Angle B with $\beta$

Angle C with $\theta$

Calculating B

This will be calculated using cosine formula as thus;

$B^2 = A^2 + C^2 - 2ACCos\beta$

Substitute values for A, C and $\beta$

$B^2 = 10^2 + 12^2 - 2 * 10 * 12 * Cos30$

$B^2 = 100 + 144 - 240 * 0.8660$

$B^2 = 100 + 144 - 207.8$

$B^2 = 36.2$

Take Square root of both sides

$B = \sqrt{36.2}$

$B = 6.0$ <em>(Approximated)</em>

Calculating $\alpha$

This will be calculated using cosine formula as thus;

$A^2 = B^2 + C^2 - 2BCCos\alpha$

Substitute values for A, B and C

$A^2 = B^2 + C^2 - 2BCCos\alpha$

$10^2 = 6^2 + 12^2 - 2 * 6 * 12 * Cos\alpha$

$100 = 36 + 144 - 144Cos\alpha$

Collect Like Terms

$100 - 36 - 144 = -144Cos\alpha$

$-80 = -144Cos\alpha$

Divide both sides by -144

$\frac{-80}{-144} = Cos\alpha$

$0.5556 = Cos\alpha$

$\alpha = cos^{-1}(0.5556)$

$\alpha = 56.2$ <em>(Approximated)</em>

Calculating $\theta$

This will be calculated using cosine formula as thus;

$C^2 = B^2 + A^2 - 2BACos\theta$

Substitute values for A, B and C

$12^2 = 6^2 + 10^2 - 2 * 6 * 10Cos\theta$

$144 = 36 + 100 - 120Cos\theta$

Collect Like Terms

$144 - 36 - 100 = -120Cos\theta$

$8 = -120Cos\theta$

Divide both sides by -120

$\frac{8}{-120} = Cos\theta$

$-0.0667= Cos\theta$

$\theta = cos^{-1}(-0.0667)$

$\theta = 93.8$ <em>(Approximated)</em>

4 0

4 years ago

Austin's truck has a mass of 2000 kg when traveling at 22.0 m/s, it brakes to a stop in 4.0 s. show that the magnitude of the br

olga2289 [7]

Since F=m•a, you want to show that a = -5.5

5 0

3 years ago

Read 2 more answers

A coal car on a train weighs 30 tons plus 1 ton per cubic yard of coal x that it carries. The total weight of a coal car is: f(x

alisha [4.7K]

Answer: Then the graph of the function f(x) will change shifting vertically down (because the negative sign in 4) by 4 tons.

Option c. The line will shift vertically down by 4 tons.

Solution:

Total weight of a coal car: f(x)=x+30

How will the graph of this function change if the coal car weight is changed to 26 tons?

The total weight of the coal car would be: g(x)=x+26

f(x)=x+30

30=26+4

f(x)=x+26+4

g(x)=x+26

f(x)=g(x)+4

Subtracting 4 both sides of the equation:

f(x)-4=g(x)+4-4

f(x)-4=g(x)

g(x)=f(x)-4

Then the graph of the function f(x) will change shifting vertically down (because the negative sign in 4) by 4 tons.

6 0

3 years ago

Read 2 more answers

Use the explicit formula to determine the 50th term in the sequence:<br> 2,5,8,11,14,...

Tju [1.3M]

Answer:

149

Step-by-step explanation:

There is a common difference between consecutive terms in the sequence.

5 - 2 = 8 - 5 = 11 - 8 = 14 - 11 = 3

This indicates the sequence is arithmetic with n th term

$a_{n}$ = a₁ + (n - 1)d

where a₁ is the first term and d the common difference

Here a₁ = 2 and d = 3 , thus

a₅₀ = 2 + (49 × 3) = 2 + 147 = 149

4 0

3 years ago

What is 7.630 in word form

Furkat [3]

Seven point six three

6 0

3 years ago

Read 2 more answers