Answer:
2.62
Step-by-step explanation:
First, write the square root as exponent.
Move the denominator to the numerator and negate the exponent.
Use log product property.
Use log exponent property.
Substitute values.
If we think about a normal curve / bell curve and the 68-95-99.7 rule, we know that the majority of data will lie within 1, 2, or 3 standard deviations from the mean. The mean is in the center of the curve, and to each side of the mean, 34% of the data lies 1 standard deviation on either side of the mean. Therefore, we need to add and subtract one standard deviation from the mean.
85 + 12 = 97
85 - 12 = 73
Correct Answer: B. 73 - 97
Hope this helps!! :)
Answer:
X= 15
Step-by-step explanation:
the above equation will be used to determine the value of x.
the above equation will be used to determine the value of x.
6x-12= 2x+20+18
6x-2x = 20+12+18
4x= 60.
X= 60/4
X= 15
x = 15
Answer:
i cannot help you get the answer to the question without more information but i can explain how to solve it, what your question is, is called a "permutation"
Step-by-step explanation:
To calculate permutations, use the equation nPr, where n is the total number of choices and r is the amount of items being selected. To solve this equation, use the equation nPr = n! / (n - r)! , an exclimation point means the factorial, say we need the factorial of 4, we would do this 4x3x2x1 go left to right, and it is not all at once. you multiply 4 times 3 which equals 12, then multiply 12 times 2... so on and so forth
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Given:
f(x) = ln(x)
n = 4
c = 3
nth Taylor polynomial for the function, centered at c
The Taylor series for f(x) = ln x centered at 5 is:
Since, c = 5 so,
Now
f(5) = ln 5
f'(x) = 1/x ⇒ f'(5) = 1/5
f''(x) = -1/x² ⇒ f''(5) = -1/5² = -1/25
f'''(x) = 2/x³ ⇒ f'''(5) = 2/5³ = 2/125
f''''(x) = -6/x⁴ ⇒ f (5) = -6/5⁴ = -6/625
So Taylor polynomial for n = 4 is:
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Hence,
The nth taylor polynomial for the given function is
P₄(x) = ln5 + 1/5 (x-5) - 1/25*2! (x-5)² + 2/125*3! (x-5)³ - 6/625*4! (x - 5)⁴
Find out more information about nth taylor polynomial here
brainly.com/question/28196765
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