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avanturin [10]
4 years ago
10

Use the substitution method to solve the system of equations

Mathematics
1 answer:
Ymorist [56]4 years ago
8 0

Answer:

We put the value of "y" into the second equation:

x * 5 = -15

x = -15 / 5

x = -3


Step-by-step explanation:


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sasho [114]

Answer:

What is the question?

Step-by-step explanation:

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4 years ago
Describe how you can use the information in a table showing a linear relationship to find the slope and y-intercept for the equa
katen-ka-za [31]
The easiest thing to find in a table showing a linear relationship is the slope. If the x is increasing by one each and every time (or cell because we are talking about tables), then the difference between each y value is the slope. Also, if you are lucky enough to have that sort of table, you can easily find the y-intercept by looking at the y value that is next to the x value of 0. Otherwise, work backward to find the y-intercept. For every x value you go down to try and get to 0, minus the y values also by the slope.
8 0
3 years ago
Express the relation in a table:(2,1),(4,5),(3,3),(1,(2)
Bad White [126]

9514 1404 393

Answer:

  see attached

Step-by-step explanation:

Once the data is entered into a spreadsheet, it is convenient to sort the table by the input values. The relation is unchanged, but it may be easier to work with that way.

The table is shown below.

5 0
3 years ago
Pat's Pizza made 21 cheese pizzas, 14 veggie pizzas, 23 pepperoni pizzas, and 14 sausage pizzas yesterday.
Sophie [7]
The probability of the next pizza not being cheese is 
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the probability of it being cheese is 21/(total)
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3 0
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Read 2 more answers
Please need help in algebra quick
Roman55 [17]

After solving |8-3p|\geq 2 we get p\geq \frac{10}{3}\,\, or\,\,p\leq  2

So, Option A is correct.

Step-by-step explanation:

We need to solve the expression:

|8-3p|\geq 2

For solving, we apply the rule that:

if |u| ≥ a and a > 0 then, u ≤ -a and u ≥ a

Applying the rule:

|8-3p|\geq 2\\8-3p\leq -2 \,\, and\,\,8-3p\geq 2\\

8-3p-8\leq -2-8 \,\, or\,\,8-3p-8\geq 2-8\\-3p\leq -10 \,\, or\,\,-3p\geq -6\\Multiply\,\,both\,\,sides\,\,by\,\,-1 (reverse\,\,the\,\,inequality\\3p\geq 10\,\, or\,\,3p\leq 6\\p\geq \frac{10}{3}\,\, or\,\,p\leq\frac{6}{3}\\p\geq\frac{10}{3}\,\, or\,\,p\leq  2

After solving |8-3p|\geq 2 we get p\geq \frac{10}{3}\,\, or\,\,p\leq  2

So, Option A is correct.

Keywords:  Absolute rule

Learn more about Absolute rule at:

  • brainly.com/question/1626495
  • brainly.com/question/2959656
  • brainly.com/question/6276835

#learnwithBrainly

5 0
3 years ago
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