All categories

3 years ago

What is the solution set of the equation 3x^2+23x-8=0

Mathematics

1 answer:

stiv31 [10]3 years ago

3 0

Answer:

x= -8 x= 1/3

Step-by-step explanation:

Solve using the quadratic formula:

a= 3

b= 23

c= -8

Note that in the picture it would be plus or minus the square root of

You might be interested in

What is -4x+4y=12 in elimination

Alborosie

I might be wrong but don’t you need two equations to do the elimination process?

4 0

3 years ago

Solve using quadratic formula.

Kazeer [188]

Answer:

Step-by-step explanation:

Just use the quadratic formula

7 0

3 years ago

How do i solve this?

ss7ja [257]

Answer:

Step-by-step explanation:

8 0

3 years ago

A triangle has vertices (-1, 2), (3, 1), and (7, 2). What is the approximate perimeter of the triangle? Round your answer to the

larisa86 [58]

Use the distance formula to find the length of the sides, then add them up to find the perimeter.

$\sf d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

For points in the form of (x1, y1), (x2, y2).

(-1, 2), (3, 1)

$\sf d=\sqrt{(3+1)^2+(1-2)^2}$

$\sf d=\sqrt{(4)^2+(-1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(3, 1), (7, 2)

$\sf d=\sqrt{(7-3)^2+(2-1)^2}$

$\sf d=\sqrt{(4)^2+(1)^2}$

$\sf d=\sqrt{16+1}$

$\sf d=\sqrt{17}$

(7, 2), (-1, 2)

$\sf d=\sqrt{(-1-7)^2+(2-2)^2}$

$\sf d=\sqrt{(-8)^2+(0)^2}$

$\sf d=\sqrt{64+0}$

$\sf d=\sqrt{64}=8$

So the perimeter will be:

$\sf 8+\sqrt{17}+\sqrt{17}\approx\boxed{\sf 16.25}$

3 0

4 years ago

(06.05 MC)

3241004551 [841]

Answer:

C (the third one)

Step-by-step explanation:

Its probably right

6 0

3 years ago

Read 2 more answers