We use different models for different types of variation. For example, linear variation is associated with the formula y=ax, or the more familiar y=mx+b (the equation of a straight line). Cubic variation: y=a*x^3. In the present case we're discussing quadratic variation; perhaps that will ring a bell with you, reminding you that y=ax^2+bx+c is the general quadratic function.
Now in y our math problem, we're told that this is a case of quadratic variation. Use the model y=a*x^2. For example, we know that if x=2, y =32. Mind substituting those two values into y=a*x^2 and solving for y? Then you could re-write y=a*x^2 substituting this value for a. Then check thisd value by substituting x=3, y=72, and see whether the resulting equation is true or not. If it is, your a value is correct. But overall I got 16!
You essentially have four triangles. The area of a triangle is: A=bh/2 (b=base length and h=height)
So the area is simply the sum of the four triangle areas...
A=(3*2)/2+(3*2)/2+(7*2)/2+(7*2)/2
A=20 ft^2
Answer:
Step-by-step explanation:
This is simple, the picture that is provided tells us the answer easily.
An angle lower than 90 degrees is called an acute angle. While one that is the same as 90 degrees is a right angle, and one that is more than 90 is obtuse.
We are asked to take a look at angle 4, we can see that is more than 90 degrees. Since 100 is the only answer with an amount higher than 90 degrees and fits the angle, it is the angle.
M=2,000÷((1−(1+0.072÷12)^(−12
×2))÷(0.072÷12))
M=89.73
Answer:
Y=-1/3x-1
Step-by-step explanation:
Y-0=-1/3(x+3)
