So, 4/3 - 2i
4/3 - 2i = 12/13 + i8/13
multiply by the conjugate:
3 + 2i/3 + 2i
= 4(3 + 2i)/(3 - 2i) (3 + 2i)
(3 - 2i) (3 + 2i) = 13
(3 - 2i) (3 + 2i)
apply complex arithmetic rule: (a + bi) (a - bi) = a^2 + b^2
a = 3, b = - 2
= 3^2 + (- 2)^2
refine: = 13
= 4(3 + 2i)/13
distribute parentheses:
a(b + c) = ab + ac
a = 4, b = 3, c = 2i
= 4(3) + 4(2i)
Simplify:
4(3) + 4(2i)
12 + 8i
4(3) + 4(2i)
Multiply the numbers: 4(3) = 12
= 12 + 2(4i)
Multiply the numbers: 4(2) = 8
= 12 + 8i
12 + 8i
= 12 + 8i/13
Group the real par, and the imaginary part of the complex numbers:
Your answer is: 12/13 + 8i/13
Hope that helps!!!
Answer:
i
Step-by-step explanation:
Answer:
r = 6
Step-by-step explanation:
Using Pythagoras' identity in the right triangle
PR² = PQ² + QR² , substitute values
(r + 4)² = r² + 8²
r² + 8r + 16 = r² + 64 ( subtract r² from both sides )
8r + 16 = 64 ( subtract 16 from both sides )
8r = 48 ( divide both sides by 8 )
r = 6
Answer:
6
Step-by-step explanation:
Answer:
answer of this question is 12150
