Permutation is different from combination because in combination the order is not a factor in considering the possible ways while permutation considers order as a factor. we are asked in this problem to evaluate 3P0 which is equal to 1.
Answer:
the general formula for the total surface area of a regular pyramid isbT. S. A. =12pl+B where p represents the perimeter of the base
Answer:
-35
Step-by-step explanation:
true
Answer:
![\mathrm{Expand}\:\left(x^{10}+10y^{12}\right)^2:\quad x^{20}+20x^{10}y^{12}+100y^{24}](https://tex.z-dn.net/?f=%5Cmathrm%7BExpand%7D%5C%3A%5Cleft%28x%5E%7B10%7D%2B10y%5E%7B12%7D%5Cright%29%5E2%3A%5Cquad%20x%5E%7B20%7D%2B20x%5E%7B10%7Dy%5E%7B12%7D%2B100y%5E%7B24%7D)
Step-by-step explanation:
![\left(x^{10}+10y^{12}\right)^2](https://tex.z-dn.net/?f=%5Cleft%28x%5E%7B10%7D%2B10y%5E%7B12%7D%5Cright%29%5E2)
![\gray{\mathrm{Apply\:Perfect\:Square\:Formula}:\quad \left(a+b\right)^2=a^2+2ab+b^2}](https://tex.z-dn.net/?f=%5Cgray%7B%5Cmathrm%7BApply%5C%3APerfect%5C%3ASquare%5C%3AFormula%7D%3A%5Cquad%20%5Cleft%28a%2Bb%5Cright%29%5E2%3Da%5E2%2B2ab%2Bb%5E2%7D)
![\gray{a=x^{10},\:\:b=10y^{12}}](https://tex.z-dn.net/?f=%5Cgray%7Ba%3Dx%5E%7B10%7D%2C%5C%3A%5C%3Ab%3D10y%5E%7B12%7D%7D)
![=\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2](https://tex.z-dn.net/?f=%3D%5Cleft%28x%5E%7B10%7D%5Cright%29%5E2%2B2x%5E%7B10%7D%5Ccdot%20%5C%3A10y%5E%7B12%7D%2B%5Cleft%2810y%5E%7B12%7D%5Cright%29%5E2)
![\black{\mathrm{Simplify}\:\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2:}](https://tex.z-dn.net/?f=%5Cblack%7B%5Cmathrm%7BSimplify%7D%5C%3A%5Cleft%28x%5E%7B10%7D%5Cright%29%5E2%2B2x%5E%7B10%7D%5Ccdot%20%5C%3A10y%5E%7B12%7D%2B%5Cleft%2810y%5E%7B12%7D%5Cright%29%5E2%3A%7D)
![\left(x^{10}\right)^2+2x^{10}\cdot \:10y^{12}+\left(10y^{12}\right)^2](https://tex.z-dn.net/?f=%5Cleft%28x%5E%7B10%7D%5Cright%29%5E2%2B2x%5E%7B10%7D%5Ccdot%20%5C%3A10y%5E%7B12%7D%2B%5Cleft%2810y%5E%7B12%7D%5Cright%29%5E2)
![\gray{\left(x^{10}\right)^2=x^{20}}](https://tex.z-dn.net/?f=%5Cgray%7B%5Cleft%28x%5E%7B10%7D%5Cright%29%5E2%3Dx%5E%7B20%7D%7D)
![\gray{2x^{10}\cdot \:10y^{12}=20x^{10}y^{12}}](https://tex.z-dn.net/?f=%5Cgray%7B2x%5E%7B10%7D%5Ccdot%20%5C%3A10y%5E%7B12%7D%3D20x%5E%7B10%7Dy%5E%7B12%7D%7D)
![\gray{\left(10y^{12}\right)^2=100y^{24}}](https://tex.z-dn.net/?f=%5Cgray%7B%5Cleft%2810y%5E%7B12%7D%5Cright%29%5E2%3D100y%5E%7B24%7D%7D)
![=x^{20}+20x^{10}y^{12}+100y^{24}](https://tex.z-dn.net/?f=%3Dx%5E%7B20%7D%2B20x%5E%7B10%7Dy%5E%7B12%7D%2B100y%5E%7B24%7D)
1/16 x 1/49 = 1/784
1/28^2 = 1/784
Your answer is B
hope this helps