In the triangle ABC, the side lengths, in order from the greatest to the least, are : AC > AB > BC.
We are given a triangle. The vertices of the triangle are A, B, and C. The measures of the angles ∠A, ∠B, and ∠C are 36°, 84°, and 60°, respectively. We need to arrange the side lengths in order from the greatest to the least.
The side lengths are proportional to their opposing angles in a triangle. It means that the side opposite the largest angle is the largest side, and vice versa. The angles arranged in descending order are : 84° > 60° > 36°. The angles arranged in descending order according to the vertices are : B > C > A. The order of the lengths of the opposite sides must be the same.
Hence, the side lengths, in order from the greatest to the least, are : AC > AB > BC.
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I believe this is how you solve it
Answer:
y=2x-7
Step-by-step explanation:
m==2
y=mx+b
9=16-7
y=2x-7
5/12-2/5=25/60-24/60
1/60
the answer is 1/60