The length is determined by multiplying the number of balls with the diameter. The answer that would come out of this is in units of centimeters.
L = (6.02 x 10^23 balls)(4 cm/ball)
L = 2.408 x 10^24 cm
Then, we use the proper conversion factor to convert centimeter to kilometer.
L = (2.408 x 10^24 cm)(1 m/100 cm)(1 km/1000 m)
L = (2.408 x 10^24)(10^5)
The answer to this item is 2.408 x 10^19 km.
Answer:
probability of lasting longer = 1.7%
Step-by-step explanation:
We are given:
x' = 14 years
μ = 12.3 years
s = 0.8 years
Thus, let's use the formula for the Z-score value which is;
z = (x' - μ)/s
Thus;
z = (14 - 12.3)/0.8
z = 2.125
From the z-distribution table attached, the p-value is ;
P(x' > 2.125) = 1 - 0.983 = 0.017 = 1.7%
Thus,probability of lasting longer = 1.7%
Answer: 547
Step-by-step explanation: The margin of error formulae is given below as
Margin of error = critical value ×(σ/√n)
Where σ = standard deviation and n is the sample size.
From our question, margin of error = 0.08
Variance is 1.691,
hence σ = √variance = √1.691
= 1.3.
We will be using a z test for our critical value this is because a soft drink manufacturer will always produce drinks more than 30 in numbers.
The critical value for a 85% confidence interval is 1.44.
Hence critical value is 1.44.
By substituting the parameters, we have that
0.08 = 1.44 × 1.3/ √n
0.08 = 1.873/ √n
By cross multiplying
0.08 × √n = 1.873
√n = 1.873/ 0.08
√n = 23.41
n = (23.41)²
n = 547.
Answer:
Step 4 is incorrect he did not divide correctly from step3 to step 4
Step-by-step explanation:
The circumference of a circle is
C = 2 * pi *r
We know the circumference is 12 pi
12pi = 2 pi *r
Divide each side by 2 pi
12 pi/2pi = 2pi r/ 2pi
6 = r
From step 3 The student did not cancel the pi in the top and the bottom on the right hand side to isolate r
In step 4 he got 6 =pi r instead of pi
Given:
The sequence formula;
Tn = 4.5n - 8 (Where n = term number)
Required:
15th term = ?
Procedure:
All you need to do is use n = 15
T15 = 4.5(15) - 8
T15 = 59.5
Conclusion:
The 15th term of the sequence is 59.5.