Answer:
Man's genotype: XᴮY
Woman's genotype: XᴮXᵇ
Daughter's genotype: XᵇXᵇ
The daughter is not the man's child.
Explanation:
Color blindness is a sex-linked trait caused by a recessive allele located in the X chromosome (Xᴮ=normal vision; Xᵇ-color blind).
Women have two X chromosomes, while men have an X and a Y chromosomes. For that reason, women need to have two recessive alleles to be color blind, while men only need one Xᵇ to be colorblind.
Since the man has normal color vision, his genotype would be XᴮY.
If the daughter is her father's, she would have inherited his dominant Xᴮ allele, so she would have normal vision. However, she is colorblind, so her genotype is XᵇXᵇ. She is not the man's daughter.
The mother also has normal color vision, but her daughter inherited a recessive allele from her, so her genotype is heterozygous XᴮXᵇ.
Under natural conditions, most populations will stabilize at a level known as the carrying capacity of the ecosystem<span>. The carrying capacity is the maximum </span>number of organisms that an ecosystem can support<span> on a continued basis.</span>
A fatty acid is a carboxylic acid with a long aliphatic chain. It can be saturated or unsaturated. In order to describe correctly the fatty acid, the length of the carbon chain should be given, the number of double bonds and the exact position of the double bonds.<span />
I would say that your correct answer is B
For the answer to the question above, I think that <span>the initial titer that has been done to her may have been done too early in the infection that detectable levels of antibody were not present yet so that's why they have to repeat it.</span>
