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2 years ago

Can you please answer? It is one of the questions on my paper that is due tomorrow!

Mathematics

1 answer:

Romashka-Z-Leto [24]2 years ago

6 0

Answer:

D x=4

Step-by-step explanation:

If the two angles are congruent, they equal the same value

2.3x +25 = 5.8x +11

Subtract 2.3x from each side

2.3x-2.3x +25 = 5.8x-2.3x +11

25 = 3.5x +11

Subtract 11 from each side

25-11 = 3.5x +11-11

14 = 3.5x

Divide each side by 3.5

14/3.5 = 3.5x/3.5

4 =x

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PLZ HELP ASAP PLZ!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

Serhud [2]

Answer:

180 degree rotation about the origin.

Step-by-step explanation:

Note that each coordinate ( x and y) have their sign changed form positive to negative. This is a rotation about the origin of 180 degrees.

7 0

3 years ago

Eli is following this recipe to bake bread rolls.He uses 900 g of flour.How much of the other ingredients does he use?Recipe: Ma

jarptica [38.1K]

18g salt
13.5g yeast
67.5mL oil
540mL water

i did it all in my head but it should be correct

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3 0

3 years ago

Use the method of undetermined coefficients to find the general solution to the de y′′−3y′ 2y=ex e2x e−x

djverab [1.8K]

I'll assume the ODE is

$y'' - 3y' + 2y = e^x + e^{2x} + e^{-x}$

Solve the homogeneous ODE,

$y'' - 3y' + 2y = 0$

The characteristic equation

$r^2 - 3r + 2 = (r - 1) (r - 2) = 0$

has roots at $r=1$ and $r=2$ . Then the characteristic solution is

$y = C_1 e^x + C_2 e^{2x}$

For nonhomogeneous ODE (1),

$y'' - 3y' + 2y = e^x$

consider the ansatz particular solution

$y = axe^x \implies y' = a(x+1) e^x \implies y'' = a(x+2) e^x$

Substituting this into (1) gives

$a(x+2) e^x - 3 a (x+1) e^x + 2ax e^x = e^x \implies a = -1$

For the nonhomogeneous ODE (2),

$y'' - 3y' + 2y = e^{2x}$

take the ansatz

$y = bxe^{2x} \implies y' = b(2x+1) e^{2x} \implies y'' = b(4x+4) e^{2x}$

Substitute (2) into the ODE to get

$b(4x+4) e^{2x} - 3b(2x+1)e^{2x} + 2bxe^{2x} = e^{2x} \implies b=1$

Lastly, for the nonhomogeneous ODE (3)

$y'' - 3y' + 2y = e^{-x}$

take the ansatz

$y = ce^{-x} \implies y' = -ce^{-x} \implies y'' = ce^{-x}$

and solve for $c$ .

$ce^{-x} + 3ce^{-x} + 2ce^{-x} = e^{-x} \implies c = \dfrac16$

Then the general solution to the ODE is

$\boxed{y = C_1 e^x + C_2 e^{2x} - xe^x + xe^{2x} + \dfrac16 e^{-x}}$

6 0

1 year ago

Write the equation 2y - 4x = 5 in the form y = mx + b.

notka56 [123]

Yea the answer is Y=2x+ 5/2

4 0

2 years ago

Vicki currently earns $35.00 an hour at her job. Thanks to her hard work, her boss is going to give her a 15% raise. How much wi

saveliy_v [14]

Answer:

$40.25 per hour

Step-by-step explanation:

If you multiply 35 by 15% you get 5.25. You can either add this on, or you can multiply by 1.15 instead of .15.

7 0

2 years ago