Let 1st integer be x and next consecutive be x+1
1/2•x + 1/5•(x+1) = 10
x/2 + x/5 + 1/5 = 10
-1/5 -1/5
x/2 + x/5 = 49/5
(x/2)•5/5 + (x/5)•2/2 = 49/5
5x/10 + 2x/10 = 49/5
7x/10 = 49/5
•10 •10
7x = 98
÷7 ÷7
x = 14 --> 1st integer
x+1 = 14+1 = 15 --> next consecutive integer
Answer:
22
Step-by-step explanation:
Answer:
Its a right angle triangle so trigonometry is used.
a is the hypotenuse, b is the adjacent.
Use sin to find a. Use tan to find b.
1) a
2) c
#1 explanation:
x^4-20x^2=-64
x^4-20x^2+64=0
(find a number that multiplies to the last number aka 64 and adds up to b aka 20)
((x-4)(x-16))^2
x= -2,2,-4,4
same for #2 w different variable and numbers
52.4/2= 26.2
26.2-3= 23.2
So the original number = 23.2
