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Brrunno [24]
3 years ago
14

Permutation question pictured! Thanks :)

Mathematics
1 answer:
lozanna [386]3 years ago
6 0

Answer:

3,160,080

Step-by-step explanation:

  • The first place can be taken by any one of the 22 students.
  • The second place can be taken by any one of the remaining 21 students.
  • The third place can be taken by any one of the remaining 20 students.
  • The fourth place can be taken by any one of the remaining 19 students.
  • The fifth place can be taken by any one of the remaining 18 students.

<em>This basically means multiplying 22, 21, 20, 19, and 18. Or, the number of permutation of 22 things taken 5 at a time.</em>

The answer is 22*21*20*19*18 = 3,160,080

<em>Using formula  nPr=\frac{n!}{(n-r)!}=\frac{22!}{(22-5)!}=\frac{22!}{17!}=(22*21*20*19*18)=3,160,080</em>

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Lapatulllka [165]

Answer:

The circles are similar.

Step-by-step explanation:

You can move the small circle 3 units to the right and then 5 units up. The center of the small circle will also be the center of the larger circle. Then you dilate the small circle by a scale factor of 5 to get the larger circle.

3 0
3 years ago
Please help ASAP 1-6
stealth61 [152]
Add your decimals to get the answer.
7 0
3 years ago
10 points!! Pls help with 5 and 6
marissa [1.9K]

Answer:

I only know number 5 so here it is

the solution for the left is: 2x6=12

the solution for the right is: 5x3+4x1=15+4=19

and the answers are: 1.12 . 2.19

5 0
3 years ago
18 POINTS! At the AoPS office, mice vary inversely with cats, that is, mice=k/cats, for some value of k. When there are 3r-19 ca
Blizzard [7]

Answer:

k=30

Step-by-step explanation:

The number of mice vary inversely with cats. This is written as:

Mice \propto \dfrac{1}{Cat} \\Mice = \dfrac{k}{Cat}

When there are 3r-19 cats, there are 2r+1 mice

2r+1 = \dfrac{k}{3r-19}\\$Cross multiply$\\k=(3r-19)(2r+1)

When there are 6r-27 mice, there are r-5 cats.

6r-27 = \dfrac{k}{r-5}\\$Cross multiply$\\k=(6r-27)(r-5)

Taking the values of k above, we have:

k=(3r-19)(2r+1) =(6r-27)(r-5)\\(3r-19)(2r+1) =(6r-27)(r-5)\\6r^2+3r-38r-19=6r^2-30r-27r+135\\$Collect like terms\\6r^2-6r^2+3r+30r-38r+27r-19-135=0\\22r-154=0\\22r=154\\$Divide both sides by 22\\r=7

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k=(3r-19)(2r+1) \\=(3*7-19)(2*7+1)\\=(21-19)(14+1)\\=2*15\\k=30

8 0
3 years ago
What’s the area of this shape
sergeinik [125]

The shape at the top is a trapezoid with width 2 cm and lengths 4 and 8 cm.

Its area is


4+8

-------- 2 cm = 12 cm^2

2


The lower part consists of two congruent triangles. The area of a triangle is

A = (1/2)(b)(h). Here, A = (1/2) (4)(5.75) = 11.5, so the area of both triangles is 23 cm^2.


Thus, the total area is (12+23) cm^2, or 35 cm^2.

3 0
4 years ago
Read 2 more answers
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